The answer is <span>f(x) = 2x2 + 3x – 3
</span>
f(x) = ax² + bx + c
a - the leading coefficient
c - the constant term
<u>We are looking for a = 2, c = -3</u>
Through the process of elimination:
The first (f(x) = 2x3 – 3) and the third choice (f(x) = –3x3 + 2) have x³ so these are not quadratic function.
In the function: <span>f(x) = –3x2 – 3x + 2
</span>a = -3
c = 2
In the function: f(x) = 2x2 + 3x – 3
a = 2
c = -3
The y's value is given in the first equation.

. Now to solve, we will, plug it's value in the second equation.

Now we have x's value, we will plug it's value in the first equation.(We can plug it in the second one too, but plugging it the first one will make it easier.)
X^2 +3x - 18 is the answer