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7nadin3 [17]
3 years ago
10

Find the equation of the circle whose center and radius are given. center ( 5.6), radius = 3

Mathematics
1 answer:
topjm [15]3 years ago
7 0

Answer:

(x-5)² + (x-6)² = 9

Step-by-step explanation:

Remember that the equation of a circle is (x - h)² + (x - k)² = r², with <em>r </em>being the radius and <em>(h,k) </em>being the center point of a circle.

Since we are already given <em>r </em>and <em>(h,k)</em>, all we need to do is plug them into the formula to find our equation.

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Write an equation of the line that passes through the given points.<br> (-1,5) and (2, - 7)
Vanyuwa [196]

Answer:

The equation of the straight line is 4x +y = 1

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given points are (-1,5) and ( 2,-7)

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m =\frac{y_{2}-y_{1}  }{x_{2} -x_{1} }  =\frac{-7-5}{2-(-1)}  = \frac{-12}{3} = -4

slope of the line m = -4

<u><em>Step(ii):-</em></u>

The equation of the straight line passing through the point (-1,5) and having slope 'm' = -4

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y - 5 = -4 ( x-(-1))

y -5 = -4 x -4

4 x + y -5 +4=0

4x +y -1 =0

<u><em>Final answer:-</em></u>

The equation of the straight line is 4x +y = 1

<u><em>  </em></u>

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