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7nadin3 [17]
2 years ago
10

Find the equation of the circle whose center and radius are given. center ( 5.6), radius = 3

Mathematics
1 answer:
topjm [15]2 years ago
7 0

Answer:

(x-5)² + (x-6)² = 9

Step-by-step explanation:

Remember that the equation of a circle is (x - h)² + (x - k)² = r², with <em>r </em>being the radius and <em>(h,k) </em>being the center point of a circle.

Since we are already given <em>r </em>and <em>(h,k)</em>, all we need to do is plug them into the formula to find our equation.

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The system of equations below represents p, the number of photo files, and v, the number of video files Helena uploaded to an on
ss7ja [257]
P + v = 650....p = 650 - v
4p + 9v = 2925

4(650 - v) + 9v = 2925
2600 - 4v + 9v = 2925
-4v + 9v = 2925 - 2600
5v = 325
v = 325/5
v = 65.....video files

p + v = 650
p + 65 = 650
p = 650 - 65
p = 585....photo files

answer : Helena uploaded 9 times as many photo files as video files
               65 * 9 = 585
5 0
3 years ago
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sergiy2304 [10]

Answer:

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Step-by-step explanation:

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7 0
2 years ago
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Find the missing term and the missing coefficient. (6a − )5a = a2 − 35a
djverab [1.8K]
So, (6a - X)*5a = Y*(a^2) - 35a 
<span>=> 6a*5a - X*5a = Y*(a^2) - 35a </span>
<span>=> 30(a^2) - X*5a = Y(a^2) - 35a

</span>30 = Y and 
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4 0
3 years ago
PLEASE HELP ASAP!!! Write an equation for the problem...
Naddika [18.5K]

Answer: 3x+16=58

Step-by-step explanation:

3x=58-16

3x=42

x=14

3 0
3 years ago
Ross needs to have a procedure done, and since he is over 65 he is on Medicare. Medicare says that according to their plan the a
Anni [7]

Answer:

\large \boxed{\$1200.00}

Step-by-step explanation:

              Let the office charge  = x

     Amount paid by Medicare = ⅞x

Amount paid by Ross = ¼(⅞x) = $262.50

 

Solve for x

\begin{array}{rcrl}\dfrac{1}{4} \left(\dfrac{7}{8}x \right ) & = & \$262.50 & \\\dfrac{7}{32}x & = & \$262.50 & \text{Multiplied the fractions}\\\\7x & = & \$8400.00 & \text{Multiplied each side by 32}\\x & = & \mathbf{\$1200.00} & \text{Divided each side by 7}\\\end{array}\\\text{The office wanted to charge } \large \boxed{\mathbf{\$1200.00}}

Check:

\begin{array}{rcl}\dfrac{1}{4} \left(\dfrac{7}{8}\times \$1200.00 \right ) & = & \$262.50\\\\\dfrac{1}{4} \left(\$1050.00 \right ) & = & \$262.50\\\\\$262.50 & = & \$262.50\\\end{array}

OK.

7 0
3 years ago
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