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Svetllana [295]
2 years ago
13

I need help with these two questions​

Mathematics
1 answer:
Galina-37 [17]2 years ago
6 0

Answer:

The first one: 19/15a

second one: b²-4ac = D

Step-by-step explanation:

for first one: take LCM and solve

for second one: you square the expression on both sides then b²= D + 4ac, then when you take 4ac to the left hand side, it becomes b²-4ac= D

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The formula gives the height of an object in free fall at time t and acceleration g.
ale4655 [162]

t must equal √2h/g but I don't see that in the choices above

3 0
3 years ago
-ELIMINATION-- <br> 4x + 9y = 9 <br> x - 3y = -6
Troyanec [42]
The first on is this answer here

6 0
3 years ago
Use the substitution method to solve.
lord [1]

Answer:

x = 7, y = 6

Step-by-step explanation:

solve for y for the first equation

2x + y = 20

-2x         -2x , eliminate 2x

y = 20-2x

now that we have found y, substitute the y in for the second equation

-5y = -6x + 12

-5(20-2x) = -6x + 12, we just changed y into 20-2x. remember that we are multiplying all of 20 - 2x by -5

-100+10x = -6x + 12, we multiplied everything from the parathesis  by -5

+100                 + 100, eliminate -100

10x = -6x + 112

+6x    +6x , eliminate 6x

16x = 112 , solve for x

x = 7

then y = 20 - 2x = 20 - 2*7 = 6

check:

2 * 7 + 6 = 20

20 = 20

-5 * 6 = -6 * 7 + 12

-30 = -42 + 12

-30 = -30

4 0
3 years ago
Verify by substitution whetherthe given functions are solutions of the given DE. Primes denote derivatives with respect to x.y!!
julia-pushkina [17]

Complete Question

The complete question is shown on the first uploaded

Answer:

y_1 is not a solution of the differential equation

 y_2 is not a solution of the differential equation

y_3 is not a solution of the differential equation

Step-by-step explanation:

The differential equation given is y'' + y' = cos2x

Let consider the first equation to substitute

y_1  = cosx  +sinx

y_1'  = -sinx  +cosx

y_1''  = -cosx -sinx

So

y_1'' - y_1'  = -cosx -sinx -sinx  +cosx

y_1'' + y_1'  = -2sinx

So

-2sinx \ne  cos2x

This means that y_1 is not a solution of the differential equation

Let consider the second equation to substitute

y_2 =  cos2x

y_2' =  -2sin2x

y_2'' =  -4cos2x

So

y_2'' + y_2'  = -4cos2x-2sin2x

So

-4cos2x-2sin2x \ne  cos2x

This means that y_2 is not a solution of the differential equation

Let consider the third equation to substitute

y_3 =  sin 2x

   y_3' =  2cos 2x

    y_3'' =  -4sin2x

So

y_3'' + y_3'  = -4sin2x  - 2cos2x

So

-4sin2x  - 2cos2x \ne  cos2x

This means  that  y_3 is not a solution of the differential equation

6 0
3 years ago
Solve for b in the literal equation y = 16x + 16b.
lubasha [3.4K]

Step-by-step explanation:

Check the above image.......

5 0
3 years ago
Read 2 more answers
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