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mariarad [96]
3 years ago
12

In a function you cannot have to of the same x values right?

Mathematics
1 answer:
LenKa [72]3 years ago
5 0
Yes, in a function you cannot have two different images for the same x.

Because if an x has more than one image, you couldn't tell what is the value of the image given that x.
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A restaurant sells 10 tacos for $8.49 of 6 of the same kind for $5.40 which is the better deal ?? Plz help me due tomorrow ✌
masya89 [10]

Answer:

10 for 8.49

Step-by-step explanation:

8.49 divided by 10 equals .849

5.40 divided by 6 equals .900

7 0
3 years ago
Name the 7 deadly sins.
arlik [135]

Answer:

1. Lust

2. Gluttony

3. Greed

4. Sloth

5. Wrath

6. Envy

7. Pride

3 0
3 years ago
Read 2 more answers
a dog eats 5 cups of food a day. a pound of food contains 10.5 cups. how much does it cost to feed the dog each day if a 50 lb b
Stells [14]
So, the dog eats 5 cups a day and 1 pound of dog food is 10.5 cups.

A 50 lb bag is<span> $22.50.

Since you're asking how much it would cost to feed it a day we need to find out how much 1 pound of food costs.

</span>22.50 / 50 = 0.45

So, it's 0.45 for 1 lb. But 1 lb is 10.5 cups, not 5.

0.45 / 5 = 0.09

So, I believe it would cost 0.09 each day to feed the dog.
3 0
3 years ago
Planet Q Is 3.6 x 10^6km
11Alexandr11 [23.1K]

Answer:

1.64×10⁷ km

Step-by-step explanation:

We know this is a triangle rectangle, so we apply the Pythagorean Theorem

QR=sqrt(PR²+PQ²)

Solving it, we will encounter in

sqrt(2.56×10¹⁴+1.296×10¹³)

to solve it, we need to bring the two numbers at the same power of ten, so we move 1.296 of one place to the left:

sqrt(2.56×10¹⁴+0.1296×10¹⁴)

we can now add the two numbers:

sqrt(2.6896×10¹⁴)

to solve this, we do the square root of 2.6896 and divide 14 by two (the index of the root is 2, so for roots' properties we can divide 14 by 2 - the index)

which gives us

1.64×10⁷

5 0
3 years ago
Which of these expressions is equivalent to 3( x-2)
Assoli18 [71]

Answer:

the answer is B because 3(x-2) is the same as 3x -2

7 0
3 years ago
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