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aksik [14]
3 years ago
9

For each table, identify the independent and dependent variables. Represent the relationship using words, an equation, and a gra

ph.
Number of Chairs Painted, p | Paint Left (oz), L
0 | 128
1 | 98
2 | 68
3 | 38
I know p is independent and L is dependent, i can come up with a graph, i just need you to come up with an equation, i can't think of one that will work, i have tried many.

please Just come up with an equation, i had a person "try" the numbers up there are parts of the equation, not the A B C D answrs, there are none. I just need an equation
like l = p * 68 or something

Mathematics
2 answers:
sergij07 [2.7K]3 years ago
7 0
(0,128),(1,98)
slope = (98 - 128) / (1 - 0) = - 30

y = mx + b
slope(m) = -30
y int (b)...ur y int is when x = 0....and u have (0,128)...so ur y int is 128
sub into ur equation
y = -30x + 128 <=== ur equation
rosijanka [135]3 years ago
5 0

Answer:

p(c)=-30c+128or \:30c+p=128

Step-by-step explanation:

1) Reading the table, the y values are constantly decreasing in 30 units. So, it is a linear function.The paint left is dependent of the amount on the number of the chairs.

2) To find out the function, we need the slope. Let's pick two coordinate points (0,128) and (1,98). And then plug it in the slope equation

m=\frac{98-128}{1-0}\Rightarrow m=-30\\

3) To find out the linear parameter, <em>b</em>. Then let's calculate it by plugging other points into the function:

128=-30(0)+b \Rightarrow b=128\\98=-30(1)+b \Rightarrow b=128

Finally,

p(c)=-30c+128

You might be interested in
Braxton has money in a savings account. The equation B = 800(1 + 0.03) can be used to calculate the amount
Sav [38]

Answer:

Braxton's initial investment is equals to (=) Pam's initial investment.

The interest on Braxton's account is less than (< ) the interest on Pam's account.

Step-by-step explanation:

Given - Braxton has money in a savings account. The equation

            B = 800(1 + 0.03)^{t} can be used to calculate the amount of money    

           in dollars, B, Braxton has in his account after t years since opening

           the account.

           Pam also has money in a savings account. The equation

           P=800(1 + 0.04)^{t}  can be used to calculate the  amount of money in

           dollars, P, Pam has in her account after t years since opening the

           account.

To find - Braxton's initial investment ..........Pam's initial investment.

             The interest on Braxton's account .....the interest on Pam's account.

Proof -

As given, Broxton equation is - 800(1 + 0.03)^{t}

               Pam equation is - 800(1 + 0.04)^{t}  

Now,

1.)

For initial investment , Put t = 0

⇒B = 800(1 + 0.03)^{0} = 800(1) = 800

  P =  800(1 + 0.04)^{0} = 800(1) = 800

As for t = 0

Braxton's equation , B = Pam's equation,P

⇒Braxton's Initial investment = Pam's initial investment.

2.)

For the interest,

As we don not have time for which the interest has to be check.

So , let the time period = 5 years

Therefore,

B = 800(1 + 0.03)^{5} = 800(1.03)^{5} = 800(1.1593) = 927.42

P =  800(1 + 0.04)^{5} = 800(1.04)^{5} = 800(1.2166) = 973.32

Now,

Interest on Braxton's account = 927.42 - 800 = 127.42 ≈ 127

Interest on Pam's account = 973.32 - 800 = 173.32 ≈ 173

∴ we get

The interest on Braxton's account is less than the interest on Pam's account.

7 0
3 years ago
I need help please!!!
PSYCHO15rus [73]

Answer:

Step-by-step explanation:

7 0
2 years ago
Solve the proportion.<br><br> 2/13=x/104<br><br> A. 16<br><br> B. 26<br><br> C. 676<br><br> D. 8
Andrej [43]

Answer:

Step-by-step explanation:

its A. 16.

4 0
4 years ago
Read 2 more answers
When 2(3/5x+2 3/4y-1/4x-1 1/2y+3) is simplified, what is the resulting expression?
erik [133]

Answer:

Option B is correct.

Step-by-step explanation:

2(\frac{3}{5}x+ 2\frac{3}{4}y-\frac{1}{4}x-1\frac{1}{2}y+3)

We need to solve the above expression.

First Convert Mix fraction into improper fraction

2(\frac{3}{5}x+ 2\frac{3}{4}y-\frac{1}{4}x-1\frac{1}{2}y+3)\\=2(\frac{3}{5}x+ \frac{11}{4}y-\frac{1}{4}x-\frac{3}{2}y+3)

Combining the like terms

=2(\frac{3}{5}x-\frac{1}{4}x+ \frac{11}{4}y-\frac{3}{2}y+3)

Solving like terms

=2(\frac{3x*4-5x}{20}+ \frac{11y-3y*2}{4}+3)\\=2(\frac{12x-5x}{20}+ \frac{11y-6y}{4}+3)\\=2(\frac{7x}{20}+ \frac{5y}{4}+3)

Multiply each term with 2

=2*\frac{7x}{20}+ 2*\frac{5y}{4}+2*3\\=\frac{7x}{10}+ \frac{5y}{2}+6

=\frac{7x}{10}+ 2\frac{1}{2}y+6

So, Option B is correct.

4 0
3 years ago
PLEASE HELP PLEASE PLEASE
PolarNik [594]
The answer is b y=-2/(x+3)-4
5 0
3 years ago
Read 2 more answers
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