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3 years ago

Can someone help me with number 5 please ???

Mathematics

1 answer:

Bumek [7]3 years ago

3 0

Answer:

Step-by-step explanation:

el español es mi idiomad

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Can someone plsss help me

balu736 [363]

Answer:

y = -5/3 x + 40

Step-by-step explanation:

The general form is y = ax + b, where a is the slope and b is the y intercept.

So immediately you can see that b must be 40, since the line crosses the y axis at 40.

The slope can be calculated by finding two "nice" points on the line that are also grid lines.

How about (0,40) and (6, 30).

Then, calculate the slope by dividing the y difference by the x difference:

(30-40)/(6-0) = -10/6 = -5/3

So C must be the answer.

6 0

2 years ago

Put the following in order from the smallest to the largest 0.2 1/2 2%

aliya0001 [1]

Answer:

2%, 0.2, 1/2

Step-by-step explanation:

0.2 = 0.20 = 20%

1/2 = 0.50 = 50%

2% = 0.02

3 0

3 years ago

Read 2 more answers

Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the

ziro4ka [17]

Answer:

a) $\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case we need to find the sample standard deviation with the following formula:

$s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}
And in order to find the sample mean we just need to use this formula:
[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}$

The sample deviation for this case is s=30.23

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=9-1=8$

The Confidence interval is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and the critical values are:

$\chi^2_{\alpha/2}=20.09$

$\chi^2_{1- \alpha/2}=1.65$

And replacing into the formula for the interval we got:

$\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

Part b

For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

4 0

3 years ago

Jori has 2 gallons of distilled water and uses 7/6 gallon in a science experiment. What fraction of a gallon does she have left?

Romashka-Z-Leto [24]

Answer:

Step-by-step explanation:

6/6 = 1 gallon

12/6 = 2 gallons

12/6 - 7/6 = 5/6

5/6 should be the answer

5 0

3 years ago

a scale model of a house is 1 ft long. The actual house is 50 ft long. In the model, the window is 11/5 in. high. how many feet

Talja [164]

Answer:

9.167

Step-by-step explanation:

11/5*50/12

5 0

3 years ago