Tell what you would do to isolate the variable. -5c = 5/24
1 answer:
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Answer:
1. 0.9544
2. 0.0228
3. 0.0228
Step-by-step explanation:
The computation is shown below;
As we know that
At Normal distribution
As per the question, the data provided is as follows
Mean = 24.4 minutes
Standard deviation = 6.5 minutes
Based on the above information
P(11.4 < X < 37.4) = P(X < 37.4) - P(X < 11.4)
= P(Z < (37.4 - 24.4) ÷ 6.5) - P(Z < (11.4 - 24.4) ÷ 6.5)
= P(Z < 2) - P(Z < -2)
= 0.9772 - 0.0228
= 0.9544
2. P(X < 11.4) = 0.0228
3. P(X ≥ 37.4) = 1 - P(X < 37.4)
= 1 - 0.9772
= 0.0228