Question

A village P is 10km from a lorry station,Q on a bearing 065°.another village R is 8km from Q on a bearing 155°.calculate; a.the distance of R from P to the nearest kilometer and b.the bearing of R from P to the nearest degree.

Answer 1

Answer:

RP = 12.8 km

38 degrees

Step-by-step explanation:

RP = $\sqrt{8^{2} + 10\\^{2} }$

RP = 12.8 km

angle = Inv sin = 8/12.8

angle 38.7°