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maw [93]
3 years ago
11

Find the area of ΔDEF to the nearest tenth. ANSWERS: A) 127.8 square units B) 46.5 square units C) 63.9 square units D) 23.3 squ

are units

Mathematics
1 answer:
Elina [12.6K]3 years ago
5 0

Answer:

C) 63.9 square units

Step-by-step explanation:

From the above diagram, we can see that the triangle has 2 sides and and angle

The formula for the area of a triangle that has 2 sides and an angle = 1/2absinθ

θ = 70°

a = DE = 8 units

b = EF = 17 units

Area of ΔDEF = 1/2 × 8 × 17 × sin 70°

Area of ΔDEF = 63.9 square units.

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Step-by-step explanation:

First, work out how many minutes are in two hours.

2 hours = 120 minutes.

Multiply 2/3 by 120

2/3 × 120 = 240/3

Simplify the the fraction

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3 years ago
2. To estimate the mean age for a population of 4000 employees, a simple random sample of 40 employees is selected. a. Would you
ANEK [815]

Answer:

Step-by-step explanation:

a.

Size of the population, N = 4000

Size of the sample, n = 40

n/N = 40/4000 = 0.01

0.01 is less than 0.05 and hence we would not us the finite population correction factor in calculating the standard error of the mean.

b.

Population standard deviation is σ = 8.2

<u>So, the standard error of x’ using the finite population correction factor is give by</u>

σ(x’) = √[(N - n)/(N - 1)] x (sigma/√n)

σ(x’) = √[(4000 - 40)/(4000 - 1)] x (8.2/√40)

σ(x’) = 1.29

<u>Standard error of x’ without using the finite population correction factor is</u>

σ(x’) = σ/√n

σ(x’) = 8.2/√40 = 1.2965

<u>There is little difference between the two values of the standard error. So we can ignore the population correction factor.</u>

c.

Let the population mean be μ

Probability that the sample mean will be within =-2 of the population mean is

P(μ– 2 < x’ < μ + 2)

At x’ = μ – 2 , we have

z = (μ – 2 – μ)/1.2965

z = -1.54

at x’ = μ  + 2, we have

z = (μ + 2 – μ)/1.2965

z = 1.54

<u>So the required probability is </u>

P(μ – 2 < x’ < μ + 2) = p(-1.54< z < 1.54)

P(μ – 2 < x’ < μ + 2) = p(z < 1.54) – p(z < -1.54)

P(μ – 2 < x’ < μ + 2) = 0.9382 – 0.0618

P(μ – 2 < x’ < μ + 2) = 0.8764

7 0
3 years ago
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