bob has 10 more marbles than larry. together they have a total of 29 marbles.How many marbles does larry have?

Find the circumference of a circle that has a 25-inch radius. Use 3.14 to approximate π.

Sergio [31]

$\huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }$

$\large\underline{ \boxed{ \sf{✰\:Important\: point's }}}$

➣ Circle:- A two-dimensional geometric figure, a line, consisting of the set of all those points in a plane that are equally distant from a given point (center).
➣ Circumference:- The line that bounds a circle or other two-dimensional figure

${ \rule{70mm}{2.9pt}}$

★ also circumference of a circle is also known as it's perimeter

➣To find circumference of circle when use formula

${ \boxed{✜\underline{ \boxed{ \sf{\: Circumference \: of \: circle= \: 2\pi \: r}}}✜}}$

➢ r = radius (25inch.)
➢ value of π is 3.14

${ \rule{70mm}{2.9pt}}$

$\large\underline{ \boxed{ \sf{✰\: Let's\:solve }}}$

$\sf{➛ \: Circumference \: of \: circle = 2 \times 3.14 \times 25} \\ \sf{➛ \: Circumference \: of \: circle =2 \times 78.5} \\ \sf{➛ \: Circumference \: of \: circle =157inch}$

★ Hence circumference of circle=157inch

$\large\underline{ \boxed{ \sf{➪\:157inch. }}}$

${ \rule{70mm}{2.9pt}}$

Hope it helps !

4 0

2 years ago

A rectangle has an area of 19.38 cm2. When both the length and width of the rectangle are increased by 1.50 cm, the area of the

Lostsunrise [7]

Answer: $5.7\ cm$

Step-by-step explanation:

Given

Rectangle has an area of $19.38\ cm^2$

Suppose rectangle length and width are $l$ and $w$

If each side is increased by $1.50\ cm$

Area becomes $A_2=35.28\ cm^2$

We can write

$\Rightarrow lw=19.38\quad \ldots(i)\\\\\Rightarrow (l+1.5)(w+1.5)=35.28\\\Rightarrow lw+1.5(l+w)+1.5^2=35.28\\\text{use (i) for}\ lw\\\Rightarrow 19.38+1.5(l+w)=35.28-2.25\\\Rightarrow l+w=9.1\quad \ldots(ii)$

Substitute the value of width from (ii) in equation (i)

$\Rightarrow l(9.1-l)=19.38\\\Rightarrow l^2-9.1l+19.38=0\\\\\Rightarrow l=\dfrac{9.1\pm\sqrt{(-9.1)^2-4(1)(19.38)}}{2\times 1}\\\\\Rightarrow l=\dfrac{9.1\pm\sqrt{5.29}}{2}\\\\\Rightarrow l=\dfrac{9.1\pm2.3}{2}\\\\\Rightarrow l=3.4,\ 5.7$