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ivann1987 [24]
3 years ago
8

Please explain how you got the answer, i dont understand the subject

Mathematics
1 answer:
KIM [24]3 years ago
5 0

Answer:

y=mx+c

We have to find the value of m and c.

Let's substitute the value of x and y from the table.

When x=1, y=15,

15= m(1)+c

m +c= 15 ------(1)

Now substitute another set of x and y values.

When x=2, y=24,

24= m(2)+c

2m +c= 24

c= 24 -2m ------(2)

Let me rewrite the two equations so that it is clearer for you to see.

m + c= 15 -----(1)

c = 24 -2m -----(2)

subst. (2) into (1):

m+ 24-2m= 15

-m= 15-24 (bring constants to 1 side, m terms to the other)

-m= -9 (simplify)

m= 9 ( divide by -1 throughout)

subst. m=9 into (2):

c= 24 -2(9)

c= 24-18

c= 6

Thus, the equation is y=9x+6.

When the cat is 3 years old, x=3.

When x=3,

y= 9(3)+6

y= 33.

Hence, the cat is 33 years old in human years.

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Part 1) The domain of the quadratic function is the interval  (-∞,∞)

Part 2) The range is the interval  (-∞,1]

Step-by-step explanation:

we have

f(x)=-x^2+14x-48

This is a quadratic equation (vertical parabola) open downward (the leading coefficient is negative)

step 1

Find the domain

The domain of a function is the set of all possible values of x

The domain of the quadratic function is the interval

(-∞,∞)

All real numbers

step 2

Find the range

The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.

we have a vertical parabola open downward

The vertex is a maximum

Let

(h,k) the vertex of the parabola

so

The range is the interval

(-∞,k]

Find the vertex

f(x)=-x^2+14x-48

Factor -1 the leading coefficient

f(x)=-(x^2-14x)-48

Complete the square

f(x)=-(x^2-14x+49)-48+49

f(x)=-(x^2-14x+49)+1

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therefore

The range is the interval

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