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Naddika [18.5K]
3 years ago
13

Differentiate. F(x) = (x3 - 3)2/3 2x f'(x) - 3 8 O f'(x) = 3 8 2x2 f'(x) 3 VX3 -8 f(x) 3 V3-8​

Mathematics
1 answer:
oee [108]3 years ago
3 0

Answer:

f'(x) =   \frac{2{x}^{2}}{ \sqrt[3]{( {x}^{3}  - 8) } }

Step-by-step explanation:

f(x) = ( {x}^{3}  - 8)^{ \frac{2}{3} }  \\  \\ f'(x) =  \frac{2}{3} ( {x}^{3}  - 8)^{ \frac{2}{3} - 1 } (3 {x}^{2}  - 0) \\  \\ f'(x) =  \frac{2}{3} ( {x}^{3}  - 8)^{ \frac{2 - 3}{3}  }  \times 3 {x}^{2} \\  \\ f'(x) =  2{x}^{2}( {x}^{3}  - 8)^{ \frac{ - 1}{3}  } \\  \\ f'(x) =   \frac{2{x}^{2}}{( {x}^{3}  - 8)^{ \frac{ 1}{3}  } } \\  \\ \huge \red{ \boxed{ f'(x) =   \frac{2{x}^{2}}{ \sqrt[3]{( {x}^{3}  - 8) } } }}

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