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3 years ago

12

100 equals 15 minus x divided by 5

1 answer:

zloy xaker [14]3 years ago

7 0

The answer is -485.

To find this we first need to get rid of the 5 in the denominator.

100 = $\frac{15 - x}{5}$

So we multiply each side by 5.

500 = 15 - x

Now we need to get rid of the 15. So we subtract 15 from both sides.

485 = -x

Then since our x is negative, we need to divide by -1.

-485 = x

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Find 63% of 77. a. 0.485 b. 48.5 c.0.818 d.81.8

8_murik_8 [283]

Answer:

b) 48.5

Step-by-step explanation:

63%= 0.63*77= 48.5

8 0

3 years ago

Elina [12.6K]

Answer:

C: Fold AX onto AB

Step-by-step explanation:

Let's draw a figure, so that you will understand the concept clearly.

We have to fold AX such that the side AX coincide with AB.

I have attached an image which visually represents this.

So the answer C. Fold AX onto AB.

Hope this will helpful.

Thank you.

3 0

3 years ago

A protein mix claims to contain a bonus of 20% more mix than the usual size container. If the bonus size contains 18 ounces of m

agasfer [191]

Answer:

The usual size of the container is 15 ounces.

Step-by-step explanation:

Consider the provided information.

A protein mix claims to contain a bonus of 20% more mix than the usual size container.

Let the usual size of the container was x ounces.

They increase 20% of usual size and the bonus size is 18 ounces.

Therefore, the new size should be:

$x+20\%x=18$

$x(1+0.20)=18$ (∴20%= $\frac{20}{100}$ =0.20)

$x(1.20)=18$

$x=\frac{18}{1.20}$

$x=15$

Hence, the usual size of the container is 15 ounces.

3 0

3 years ago

Angela is going on vacation to Mexico. She needs to buy new shirts for her trip. She buys 10 new shirts that cost her a total of

vivado [14]

Angela purchased 4 casual shirts and 6 dressy shirts.

$25 × 6 = $150
$18 × 4 = $72

$150 + $72 = $222

hope this helped :)

8 0

3 years ago

Suppose that there are 15 antennas in a store, of which 3 are defective. Assume all the defectives and all the functional antenn

ohaa [14]

Answer:

Step-by-step explanation:

Total number of antenna is 15

Defective antenna is 3

The functional antenna is 15-3=12.

Now, if no two defectives are to be consecutive, then the spaces between the functional antennas must each contain at most one defective antenna.

So,

We line up the 13 good ones, and see where the bad one will fits in

__G __ G __ G __ G __ G __G __ G __ G __ G __ G __ G __ G __G __

Each of the places where there's a line is an available spot for one (and no more than one!) bad antenna.

Then,

There are 14 spot available for the defective and there are 3 defective, so the arrange will be combinational arrangement

ⁿCr= n!/(n-r)!r!

The number of arrangement is

14C3=14!/(14-3)!3!

14C3=14×13×12×11!/11!×3×2

14C3=14×13×12/6

14C3=364ways

7 0

3 years ago