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3 years ago

Identify the transformations y = |x| ‐ 6

Mathematics

1 answer:

siniylev [52]3 years ago

4 0

Thé transformation is that the function moved 6 units down

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Solve for X: 39 - 7x = -4 (7x + 7) = 4

gtnhenbr [62]

Subtract 39 from both sides

-7x = -4 - 39

Simplify -4 - 39 to -43

-7x = -43

Divide both sides by -7

x = -43/-7

Two negative make a positive

x = 43/7

For the second equation;

Simplify brackets

7x + 7 = 4

Subtract 7 from both sides

7x = 4 - 7

Simplify 4 - 7 to -3

7x = -3

Divide both sides by 7

x = -3/7

4 0

3 years ago

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In what area did Taft's contributions equal or surpass Roosevelt's?

arsen [322]

Answer:

The area in which Taft contributed equal or surpass Roosevelt's was in conservation.....

Step-by-step explanation:

U 2 can help me by marking as brainliest........

6 0

2 years ago

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Find the side length of a square whose area is 121 ft^2

kogti [31]

Answer:

The side length is 11 ft

Step-by-step explanation:

The area of a square is given by

A = s^2 where s is the side length

121 ft^2 = s^2

Take the square root of each side

sqrt( 121 ft^2) = sqrt(s^2)

11 ft = s

The side length is 11 ft

8 0

3 years ago

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If m < 0 and b > 0, the graph of y = mx + b does not pass through which quadrant?

stiks02 [169]

Answer:

Quadrant III

Step-by-step explanation:

The attached picture shows graph of 4 such linear functions with the conditions given in the problem. ALL of them DO NOT pass through Quadrant III.

The graphs shown are of the functions:

$y=-2x+1$

$y=-3x+3$

$y=-x+0.5$

$y=-5x+2$

So, any linear function of the form $y=mx+b$ with $m$ and $b>0$ does not pass through Quadrant III. Answer choice 3 is correct.

8 0

3 years ago

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You recently sent out a survey to determine if the percentage of adults who use social media has changed from 66%, which was the

il63 [147K]

Answer:

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

Of the 2809 people who responded to survey, 1634 stated that they currently use social media.

This means that $n = 2809, \pi = \frac{1634}{2809} = 0.5817$

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a pvalue of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.327$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 - 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.56$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 + 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.6034$

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).

6 0

2 years ago