To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
A consistent system of equations is a system with intersecting lines and lines that have the same equation.
A consistent system is the system of equations with at least one solution or infinite number of solutions.
So , the intersecting lines will always have a solution and the lines with the same equation will have infinite number of solution.
The graph of a system of equations with different slopes will have no solutions. Correct option in "Never"
If the system of equations have different slopes then the equations are not parallel, hence the equations will always have a solution.
Answer: 43/10
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Step-by-step explanation:
Answer:
1+3i
Step-by-step explanation:
i is a variable. -1 has an absolute value of 1. 3i is multiplying i by 3.
Answer:
13
Step-by-step explanation:
243.50 - 130.50 = 104
104 ÷ 8 = 13
