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frez [133]
3 years ago
6

If 4A=5B and 6B=7C, find A:B.C​

Mathematics
1 answer:
koban [17]3 years ago
6 0

Answer:

A:B:C = 35:28:30

Step-by-step explanation:

(Idk if it is the correct process but I remember doing it like this)

First...

4A = 5B

or, A/B = 5/4

= 5×7/4×7

= 35/28

Next...

6B = 7C

or B/C = 7/6

= 7×5/6×5

= 28/30

(Since there are two Bs which are 4 and 7, we divided it like 4×7 and 7×4 so they would be equals since both Bs should have same value. So we need to divide both denominator and numinator with same number.)

so...

A:B:C = 35 : 28 : 30

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