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xeze [42]
3 years ago
9

PLEASE HURYYYY Solve the inequality.−2 <m – 7

Mathematics
2 answers:
amm18123 years ago
8 0
The answer is m > 5 or 5 <span>< m</span>
soldi70 [24.7K]3 years ago
6 0
Here you go, hope it helps:)

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PLS HELP I WILL GIVE HRAINLIEST JUST PLSSSSSSSS
olchik [2.2K]
There will have to be 5 because of the 4
7 0
3 years ago
The voltage in a circuit is the product of two factors, the resistance and the current. If the voltage is 6ir + 15i + 8r+20, fin
zhuklara [117]

Answer:

  • resistance: (2r +5)
  • current: (3i +4)

Step-by-step explanation:

The factors of the given expression are ...

  6ir +15i +8r +20 = (3i +4)(2r +5)

Which factor is current and which is resistance is not clear. Usually, resistance is referred to using the variable r, so we suppose the expressions are supposed to be ...

  resistance: (2r +5)

  current: (3i +4)

6 0
3 years ago
8 x - 4 (5 - x) = -44
Sphinxa [80]

8 x - 4 (5 - x) = -44

mutiply the bracket by -4

(-4)(5) = -20

(-4)(-x)= 4x

8x-20+4x= -44

8x+4x-20= -44 ( combine like terms )

12x-20= -44

move -20 to the other side

sign changes from -20 to +20

12x-20+20= -44+20

12x= -44+20

12x= -24

divide both sides by 12

12x/12= -24/12

Answer: x= -2

3 0
3 years ago
A random sample of 10 shipments of stick-on labels showed the following order sizes.10,520 56,910 52,454 17,902 25,914 56,607 21
sammy [17]

Answer:

Confidence Interval: (21596,46428)

Step-by-step explanation:

We are given the following data set:

10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{340119}{10} = 34011.9

Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821

S.D = \sqrt{\frac{2711418821}{9}} = 17357.09

Confidence interval:

\mu \pm t_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621

34011.9 \pm 2.2621(\frac{17357.09}{\sqrt{10}} ) = 34011.9 \pm 12416.20 = (21595.7,46428.1) \approx (21596,46428)

7 0
3 years ago
Please provide the answer?
Brums [2.3K]

Using the given table:

a) the average rate of change is 32.5 jobs/year.

b) the average rate of change is 12.5 jobs/year.

<h3>How to find the average rate of change?</h3>

For a function f(x), the average rate of change on an interval [a, b] is:

\frac{f(b) - f(a)}{b - a}

a) The average rate of change between 1997 and 1999 is:

A = \frac{695 - 630}{1999 - 1997}  = 32.5

So the average rate of change is 32.5 jobs/year.

b) Now the interval is 1999 to 2001.

The rate this time is:

A ' = \frac{720 - 695}{2001 - 1999} = 12.5

So the average rate of change is 12.5 jobs/year.

If you want to learn more about average rates of change:

brainly.com/question/8728504

#SPJ1

3 0
1 year ago
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