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agasfer [191]
3 years ago
7

Find the slope of the line using the ordered pairs (4-3) (7.-2)

Mathematics
1 answer:
lakkis [162]3 years ago
5 0

Answer:

m = 1/3

Step-by-step explanation:

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Mrrafil [7]

Answer:

1.)41.5    2.)33.68

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
Points P(-2,10), Q(0,8), and R are collinear
pantera1 [17]
<span><span>so assuming the sum of the shortest distance added to exactly the longest distance,
We could not be off by more than.
 is the sum,
and it differs from  by,
so the points are not colinear.</span><span>
</span></span>
4 0
4 years ago
300 students in a high school freshman class are surveyed about what kinds of pets they have. Of the 300 students, 200 have a do
katrin2010 [14]

This Question is not complete

Complete Question:

300 students in a high school freshman class are surveyed about what kinds of pets they have. Of the 300 students, 200 have a dog, 180 have a cat, and 150 have a cat and a dog. Using this information, answer each of the following questions, Let D be the event that a randomly selected student has a dog and C be the event that a randomly selected student has a cat.

a . What is P(D), the probability that a student in the class has a dog?

b. What is P(C), the probability that a student in the class has a cat?

c. What is P(D and C), the probability that a student in the class has a dog and a cat?

d. What is P(D or C), the probability that a student in the class has a dog or a cat?

Answer:

a. 2/3

b) 3/5

c) 1/2

d) 19/ 15 = 1 4/15

Step-by-step explanation:

The formula for probability =

Number of possible outcomes ÷ Number of events.

Total number of Students = 300

Number of Students that have a dog = 200

Number of Students that have a cat = 180

Number of Students that have a dog and cat = 150

a. What is P(D), the probability that a student in the class has a dog?

In the question, the given data is interpreted as :

Number of possible outcomes = 200

Number of events = 300

P(D) = 200/300

= 2/3

Therefore, the probability that a student has a dog = 2/3

b. What is P(C), the probability that a student in the class has a cat?

In the question, the given data is interpreted as :

Number of possible outcomes = 180

Number of events = 300

P(D) = 180/300

= 3/5

Therefore, the probability that a student has a cat = 3/5

c. What is P(D and C), the probability that a student in the class has a dog and a cat?

In the question, the given data is interpreted as :

Number of possible outcomes = 150

Number of events = 300

P(D) = 150/300

= 1/2

Therefore, the probability that a student has a dog and cat = 1/2

d. What is P(D or C), the probability that a student in the class has a dog or a cat?

The is calculated as

P(D) + P(C)

In the above question,

P(D) is calculated as 2/3

P(C) is calculated as 3/5

Therfore, P(D or C), the probability that a student in the class has a dog or a cat is calculated as:

= 2/3 +3/5

= 19/15 = 1 4/15

7 0
3 years ago
Harold sorted his jellybeans into two jars. He likes the purple ones best and the black ones next best, so these are both in one
charle [14.2K]

Answer: 30%

The probability of black is 60% and the probability of orange is 50%. The probability of getting both is then the product of their probabilities:

                          60% multiplied by 50%=0.6 times 0.5=0.3 of 30%

HOPE THIS HELPS!!!!!!!:)

3 0
3 years ago
A farmer has chickens and cows. You ask the farmer how many chickens he has, and how many cows he has. The farmer has 28 healthy
crimeas [40]
Set the number of chickens as x and number of cows as <span>y
</span>so the farmer has total 28 animals
so x+y=28 
you know that since the animals are healthy
chickens will have 2 legs    and
cows will have 4 legs
the total number of legs are 64
so 2x+4y=64
since you want to find the number of cows 
so from the first equation <span>x+y=28
</span>we will get another equation <span>x=28-y
</span>then plug into <span>2x+4y=64
2(28-y)+4y=64
56-2y+4y=64
56+2y=64
-56      -56
2y=8
y=4
</span>

3 0
4 years ago
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