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3 years ago

Factor. 2x2−3x−5 (2x+5)(x−1) (x−5)(2x+1) (2x−5)(x−1) (2x−5)(x+1)

Mathematics

2 answers:

Anvisha [2.4K]3 years ago

8 0

Answer:

Step-by-step explanation:add all of the numbers with x to get 15. then add the numbers without the x (x=15) (without x = 33) subtract 33 from 15 and you'll get 18

Likurg_2 [28]3 years ago

7 0

Answer:

Step-by-step explanation

You do the brackets first
The answer to the brackets is : 0
Because you also times the others by 0 the answer must be 0.

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Sketch the piecewise function shown in the picture. Where is the graph increasing, decreasing, and constant?

sladkih [1.3K]

Answer:

that is a lot of things

Step-by-step explanation:

I don't know. I thought I did. sorry.

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3 years ago

Y=4x−9<br> Complete the missing value in the solution to the equation

igomit [66]

Answer:

The possibilities for solutions are pretty much endless, but an example of one would be (1, -5).

Step-by-step explanation:

You can plug in any value for x and then solve for y or plug in any value for y and then solve for x.

4 0

3 years ago

How do i do this x:2=2

Leno4ka [110]

It’s a ratio and for it to equal 2 x will equal 4

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3 years ago

Graph the following piecewise function on a separate piece of graph paper and upload your graph below.

Alecsey [184]

ANSWER

To graph the function

$f(x)=\left \{ {{x+4\:\:if\:\:-4\leq x$

follow the steps below.

1. Find y- intercept by plugging in $x=0$ .

$x=0$ is on the interval, $-4\leq x$ , so we substitute in to

$f(x)=x+4$

$\Rightarrow f(0)=0+4$

$\Rightarrow f(0)=4$

Hence the y-intercept is $(0,4)$

2. Find x-intercept by setting $f(x)=0$

This implies that

$x+4=0,$ on $-4\leq x$

or

$2x-1=0$ on $3\leq x$

We now solve for $x$ on each interval,

$x=-4,$ on $-4\leq x$

or

$x=\frac{1}{2}$ on $3\leq x$

But observe that

$x=\frac{1}{2}$ does not belong to $3\leq x$

This means it can never be an intercept for this piece-wise function.

Hence our x-intercept is $(-4,0)$

3. Plotting the boundaries of the interval.

For $f(x)=x+4$ on $-4\leq x$

$f(-4)=-4+4$

$\Rightarrow f(-4)=0$ .

This point $(-4,0)$ coincides with the x-intercept.

$f(3)=3+4$

$f(3)=7$

So we have the point $(3,7)$ . But note that $x=3$ does not belong to this interval so we plot this point as a hole.

For $f(x)=2x-1$ on $3\leq x$

$f(3)=2(3)-1$

$\Rightarrow f(3)=5$

So we plot $(3,5)$

$f(6)=2(6)-1$

$\Rightarrow f(6)=11$

So we plot $(6,11)$ also as a hole.

Plotting all these points we can now graph the function,

$f(x)=\left \{ {{x+4\:\:if\:\:-4\leq x$

See attachment for graph.

7 0

3 years ago

Read 2 more answers

How would you write a word phrase for the algebraic expression d/5+2? The difference between the quotient of d and 5 and 2? The

krek1111 [17]

Answer: The word phrase for this expression is the last option, "The sum of the quotient of d and 5 and 2." d is being divided by 5, so we would use "quotient of d and 5" for that part, and then we would add the "sum" because d/5 is being added to 2.

5 0

3 years ago