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const2013 [10]
4 years ago
11

David rowed a boat upstream for three miles and then returned to point he started from. The entire journey took four hours. The

speed of the stream is one mile per hour. Find David's speed in still water. (Hint: speed = distance ÷ time, upstream speed = speed of the boat – speed of the stream, and downstream speed = speed of the boat + speed of the stream) David's speed in still water is ____ miles per hour.
Mathematics
1 answer:
CaHeK987 [17]4 years ago
7 0
To solve for the time it takes to travel a certain distance at a certain speed, use the formula,
                                     time = distance / speed

Given that the entire journey takes four hours, add up the time it takes David to row upstream with that of him travelling downstream. This is mathematically represented as,

                              total time = time upstream + time downstream

                                         4 = 3/(x - 1) + 3/(x +1)

Solving for x in the equation gives 2. Thus, David's speed in still water is 2 miles per hour. 
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lys-0071 [83]

Answer:

L= Q_1 - 1.5*IQR = 210 -1.5*40 =150

U= Q_3 + 1.5*IQR = 250 +1.5*40 =310

And if we analyze the info provided we have 500 values

Tails: 160,165,167,171,175,...,268,269,269,269,270,270

So as we can see on the tails any values is <150 or >310 so then for this case we cannot consider as outliers any of the values on the tails of the distribution.

Step-by-step explanation:

For this case we have the 5 number summary

(160,210,220,250,270)

So then we have:

minimum = 160 , Q1 = 210, Q2= Median=220, Q3 = 250, Max=270

If we find the interquartile range we got:

IQR = Q_3 -Q_1 = 250-210 =40

For this case we need to find the lower and upper limit with the following formulas:

L= Q_1 - 1.5*IQR = 210 -1.5*40 =150

U= Q_3 + 1.5*IQR = 250 +1.5*40 =310

And if we analyze the info provided we have 500 values

Tails: 160,165,167,171,175,...,268,269,269,269,270,270

So as we can see on the tails any values is <150 or >310 so then for this case we cannot consider as outliers any of the values on the tails of the distribution.

4 0
4 years ago
A cylinder has a base radius of 4m and a height of 6m. What is its volume in cubic m, to the nearest tenths place?
Ronch [10]
<h3>Answer:</h3>

301.6 cubic meters

<h3>Step-by-step explanation:</h3>

A cylinder is a shape with straight sides with circular or oval cross-sections. We know that the cylinder in the question must be a circular cylinder due to its radius description. 

Volume Formula

A circular cylinder has a volume of V=\pi r^2h. In this equation, V is the volume, r is the radius, and h is the height. The question tells us that r=4m and h=6m. So, we can plug these values into the formula.

Solving for Volume

To solve plug the values into the formula and rewrite the equation.

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Next, apply the exponents.

  • V=\pi *16*6

Then, multiply the constants.

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Finally, multiply the remaining terms. Remember to use the pi button on the calculator and not an estimation to get a more exact value.

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Make sure your answer is rounded to the correct digit. This means that the volume must be 301.6 cubic meters.

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