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Zina [86]
3 years ago
10

What is simply ford -4n^0 × 3n^-2

Mathematics
1 answer:
Paha777 [63]3 years ago
6 0
<span>-4n^0 × 3n^-2
= -4(1) </span>× 3n^-2
= -4× 3n^-2
= -12 n^-2
= -12/n^2
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9 1/3 to a fraction show me
alekssr [168]

Answer:

\frac{28}{3}

Step-by-step explanation:

If you mean an improper fraction, then 9\frac{1}{3}=\frac{(9*3)+1}{3}=\frac{27+1}{3}=\frac{28}{3}

3 0
2 years ago
Can someone help me with this problem? thank you!
lara [203]

Answer:

154

Step-by-step explanation:

The area of a triangle is equal to 1/2

the base times the height.

1/2 times (base) times(height)

Substitute the values of the base  b=22 and height h=14 into the formula for the area of a triangle.

1/2 times 22 times 14

Cancel the common factor of 2

Multiply

11 by 14

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7 0
2 years ago
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Element X decays radioactively with a half-life of eight minutes. If there are 800 g of element X, how long, to the nearest 10th
Harman [31]

Answer: 41.5 min

Step-by-step explanation:

This problem can be solved with the Radioactive Half Life Formula:  

A=A_{o}.2^{\frac{-t}{h}} (1)

Where:  

A=22 g is the final amount of the radioactive element

A_{o}=800 g is the initial amount of the radioactive element  

t is the time elapsed  

h=8 min is the half life of the radioactive element  

So, we need to substitute the given values and find t from (1):  

22 g=(800 g) 2^{\frac{-t}{8 min}} (2)  

\frac{22 g}{800 g}=2^{\frac{-t}{8 min}} (3)  

\frac{11}{400}=2^{\frac{-t}{8 min}} (4)  

Applying natural logarithm in both sides:  

ln(\frac{11}{400})=ln(2^{\frac{-t}{8 min}}) (5)  

-3.593=-\frac{t}{8 min}ln(2) (6)  

Clearing t:

t=41.46 min \approx 41.5 min This is the time elapsed

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Delicious77 [7]
It shows the SAS congruence theorem

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3 years ago
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Suppose it was –5 degrees Celsius at 6:00 a.m. By noon, the temperature had Increased by 11 degrees. What was the temperature at
alukav5142 [94]

Answer:

6

Step-by-step explanation:

11 - -5 = 6

8 0
4 years ago
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