
In the Triangle BCD, Angle B is 90° since tangent and radius are perpendicular to one another.
Now, let's find Angle C using Angle sum property of a triangle.





Now, we know that Angle made by an arc on the centre is twice the Angle made by same arc on boundary of circle, hence we can infer that :




So, the required value of x is 9
im pretty sure the answer is 7 9/40
Answer:
the third option
Step-by-step explanation:
60.2
Step-by-step explanation:
a^2 + b^2 = c^2
40^2 + 45^2 = c^2
1600 + 2025 = c^2
3625 = c^2
the square root of 3625 is 60.2