Answer:
Step-by-step explanation:Since we want to know how much time elapsed since the object was launched until it ht the ground. At the ground, the height is 0.
Therefore the equation h(t) = 80t – 16t2 becomes 0= 80t – 16t2
Solving the equation for t gives 80t =16t2 or 16t=80 or t=5sec
The object hits the ground 5 seconds after it is launched.
Answer:
37 1/8
Step-by-step explanation:
The problem probably assumes direct variation
y=kx
IF so, then plug in the values and solve for k
27=k(8)
k = 27/8
y= (27/8)x. Now let x = 11
y = (27/8)11 = 27(11)/8 = 37.125 = 37 1/8
y = 37 1/8
the problem is making some assumption about the relation between x and y. The simplest assumption that's likely is direct variation, that x and y are linearly related. The graph is a straight line through the origin with slope = 27/8
The total area is 625 because 25 x 5 = 125. 125 x 5 = 625. that is how you get your answer
