<span>On the number line, p would be to the left of 2/3. The sum of p and 2/3 equals 0.</span>
I hope this helps you
x^2-5x-6
x -6
x +1
(x-6)(x+1)
x^2+5x-6
x +6
x -1
(x+6)(x-1)
Y=x^2+12x+30
8x-y=10
sub x^2+12x+30 for y in the secodn equaiton
8x-(x^2+12x+30)=10
8x-x^2-12x-30=10
-x^2-4x-30=10
times -1
x^2+4x+30=-10
add 10 both sides
x^2+4x+40=0
use quadratic formula
we find that we have 2 imaginary roots and therefor are not on the real plane, they are not plotted on the imaginary plane
no real solution
x=-2+6i or -2-6i
the interseciton on the imaginary plane is
(-2+6i, -26+48i) or (-2-6i,-26-48i)
9514 1404 393
Answer:
(a) y = 5
Step-by-step explanation:
The equation of a horizontal line can be written as ...
y = constant
In order to make that line pass through a given point, the constant must match the y-coordinate of the point. Here, that is 5.
y = 5
