Answer:
The number of calculators is 4871
Step-by-step explanation:
If we integrate dx/dt we get x, which is the number of calculators. To find the number of calculators between the beginning of third week to the end of fourth week (the beginning of fifth week), this integration must be evaluated at t between 3 and 5.
the result of the integration is:
to be evaluated between 3 and 5, which is:
9514 1404 393
Answer:
$3291.60
Step-by-step explanation:
If the loan is amortized in the usual way, the monthly payment is ...
A = P(r/12)/(1 -(1 +r/12)^(-12t)) . . . . . loan of P at rate r for t years
A = $15,000(0.081/12)/(1 -(1 +0.081/12)^(-12·5)) ≈ $304.86
The total of payments is ...
(60 months) × ($304.86/month) = $18,291.60
Then the profit to the bank is ...
$18,291.60 -15,000 = $3,291.60 . . . bank profit
Answer:
9........I will post process in comments because you are needing this right now
Answer:
1/7 (option d) of the sensors on the satellite have been upgraded
Step-by-step explanation:
Each unit contains the same number of non-upgraded sensors
number of non-upgraded sensors for each module (nus)
total number of upgraded sensors on the satellite (tus)
satellite is composed of 30 modular units
total number of non-upgraded sensors on the satellite (tnus):
tnus=30*nus
total number of sensors on the satellite (ts):
ts=tnus+tus = 30*nus + tus (I)
The number of non-upgraded sensors on one unit is 1/5 the total number of upgraded sensors on the entire satellite
nus=(1/5)*tus
tus = 5 * nus (II)
Fraction of the sensors on the satellite have been upgraded (FU):
FU = tus/ts
Using I and II
FU= (5* nus)/(30*nus + tus)
FU = (5* nus)/(30*nus + 5 * nus)
FU = (5* nus)/(35*nus)
FU = 1/7
1/7 (option d) of the sensors on the satellite have been upgraded
Answer:
Equation: 5w = c
Step-by-step explanation:
k is a constant of proprtionality
» Therefore, equation becomes:
