Find the area of an equilateral triangle with a side of 6 inches

I WILL GOVE YOU BRAINLIEST IF CORRECT YOU HAVE TO EXPLAIN WHY IT IS THO

Assoli18 [71]

Answer:

G

Step-by-step explanation:

If you do a common denominator of 30 for all of them

F would be 10/30

g would be 8/30

h would be 24/30

and j is obviously 14/30

3 0

2 years ago

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Beau's recipe fro granola bars calls for 3 1/2 cups of oatmeal. He only has 1/6 scoop. How many scoops of oatmeal will he need t

natulia [17]

$\boxed{21}$ scoops of oatmeal will he need to complete the recipe.

Further explanation:

Given:

Beau's recipe from granola bars calls for $3\dfrac{1}{2}$ cups of oatmeal.

He only is $\dfrac{1}{6}$ scoop.

Explanation:

The cups of oatmeal called for the recipe is $3\dfrac{1}{2}.$

Solve the improper fraction $3\dfrac{1}{2}.$

$\begin{aligned}{\text{Fraction}}&=\frac{{2 \times 3 + 1}}{2}\\&=\frac{{6 + 1}}{2}\\&=\frac{7}{2}\\\end{aligned}$

The Beau has $\dfrac{1}{6}{\text{ scoop}}.$

The number of scoops required to complete the recipe can be obtained as follows,

$\begin{aligned}N&=\frac{{{\text{total cups of oatmeal}}}}{{{\text{the fraction of scoop Beau has}}}}\\&=\frac{{\frac{7}{2}}}{{\frac{1}{6}}}\\&= \frac{7}{2} \times6\\&=\frac{{42}}{2}\\&= 21\\\end{aligned}$

Number of scoops required to complete the oatmeal is $21{\text{ scoops}}.$

Therefore, $\boxed{21}$ scoops of oatmeal will he need to complete the recipe.

Learn more:

1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.

2. Learn more about equation of circle brainly.com/question/1506955.

3. Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: Middle School

Subject: Mathematics

Chapter: Fractions

Keywords: fraction, Beau’s recipe, granola bars, calls, 3 1/2 cups of oatmeal, scoops, recipe, ratio, 1/6 scoop, complete the recipe.

5 0

2 years ago

8.23 A manufacturing company produces electric insulators. You define the variable of interest as the strength of the insulators

Kitty [74]

Answer:

The 95% confidence interval estimate for the population mean force is (1691, 1755).

Step-by-step explanation:

According to the Central Limit Theorem if we have an unknown population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally.

The sample selected here is n = 30.

Thus, the sampling distribution of the sample mean will be normal.

Compute the sample mean and standard deviation as follows:

$\bar x=\frac{1}{n}\sum x=\frac{1}{30}\times 51702=1723.4\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{30-1}\times 232561.2}=89.55$

Construct a 95% confidence interval estimate for the population mean force as follows:

$CI=\bar x\pm z_{\alpha /2}\times\frac{s}{\sqrt{n}}$

$=1723.4\pm 1.96\times\frac{89.55}{\sqrt{30}}\\\\=1723.4\pm 32.045\\\\=(1691.355, 1755.445)\\\\\approx (1691, 1755)$

Thus, the 95% confidence interval estimate for the population mean force is (1691, 1755).

3 0

3 years ago

You cut 63 meters of rope into 9 equal pieces. How long is each equal piece of горе?

kogti [31]

Answer:

7 meters. 63/9 = 7.

3 0

2 years ago

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Evaluate the Riemann sum for (x) = x3 − 6x, for 0 ≤ x ≤ 3 with six subintervals, taking the sample points, xi, to be the right e

DENIUS [597]

Hello,

Reminders:
$$\sum_{i=1}^{n} i= \dfrac{n(n+1)}{2}$


$
$$ \sum_{i=1}^{n} i^2= \dfrac{n(n+1)}{2}$

$
$$ \sum_{i=1}^{n} i^3= \dfrac{n^2(n+1)^2}{4} $
$

$n=6\\
x_{0}=0\\
x_{n}=3\\
\Delta= \dfrac{x_n-x_0}{n}=0.5\\

$
$x_{i} =0+\Delta*i= \frac{i}{2}$

$\sum_{i=1}^{n}\ \Delta*f(x_{i})=\sum_{i=1}^{6}\ \dfrac{i^3/8-6i}{2}$
$$= \dfrac{1}{2}\sum_{i=1}^{6} (\frac{i^3}{8} -6i)=\dfrac{1}{16}*\frac{(6*7)^2}{4}- \frac{9*7}{2}= -3.9575$

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xls

8 0

3 years ago

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