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3 years ago

Ill give brainliest - please help ASAP WITH THE WORK THO PLEASE?

Mathematics

1 answer:

ohaa [14]3 years ago

4 0

Answer:

we have.

11x=½(16x+16+50)

22x=16x+66

22x-16x=66

6x=66

x=66/6

x=11

118°=½(6x-11+181)

236=6x+170

6x=236-170

x=66/6

x=11°

34°=½(arcAK-arc LN)

34×2=(110-arc LN)

arc LN =110-68

arc LN=42°

<L=½(arc EN-arc KM)

<L=½(139°-73°)

<L=33

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Triangle ABC has side lengths a= 24, b= 40, and c= 55. What is the measure of angle C? 83.6° 116.2° 23.0° 40.7°

Harlamova29_29 [7]

<h3>Answer: 116.2°</h3>

Work Shown:

$c^2 = a^2 + b^2 - 2ab\cos(C)\\\\55^2 = 24^2 + 40^2 - 2*24*40\cos(C)\\\\3025 = 576 + 1600 - 1920\cos(C)\\\\3025 = 2176 - 1920\cos(C)\\\\3025 - 2176 = -1920\cos(C)\\\\849 = -1920\cos(C)\\\\-1920\cos(C) = 849\\\\\cos(C) = (849)/(-1920)\\\\\cos(C) \approx -0.4421875\\\\C \approx \cos^{-1}(-0.4421875)\\\\C \approx 116.243535748231^{\circ}\\\\C \approx 116.2^{\circ}\\\\$

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2 years ago

The area of a rectangle is 5/6 sq foot. The width is 2/3 foot. The length of the rectangle is how many feet

max2010maxim [7]

Answer:

The answer is

$\frac{5}{4} \\$

Step-by-step explanation:

Area of a rectangle = length × width

Since we are finding the length

<h3> $length = \frac{area}{width} \\$ </h3>

From the question

area = 5/6 sq. feet

width = 2/3 foot

Substitute the values into the above formula and solve for the length

The length is

$length = \frac{5}{6} \div \frac{2}{3} \\ = \frac{5}{6} \times \frac{3}{2} \\ = \frac{5}{2} \times \frac{1}{2} \\ = \frac{5}{4}$

We have the final answer as

$\frac{5}{4} \\$

Hope this helps you

7 0

3 years ago

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Express the following repeating decimal as a fraction in simplest form.

Ivenika [448]

Answer:

$0.\overline{369} = \frac{41}{111}$

Step-by-step explanation:

x = 0.369369369...

10x = 3.69369369...

100x = 36.9369369...

1000x = 369.369369...

1000x - x = 369

999x = 369

$x = \frac{369}{999} \\\\x = \frac{123}{333}\\\\x = \frac{41}{111}$

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3 years ago

A sequence is defined recursively by the following rules: f(1)=3f(n+1)=2⋅f(n)−1 Which of the following statements is true about

Radda [10]

Answer:

f(2)=5

f(5)=33

Step-by-step explanation:

The given formula, that recursively defines the sequence is

$f(1) = 3 \\ f(n + 1) = 2f(n) - 1$

When n=1, we obtain;

$f(1+ 1) = 2f(1) - 1 \\ f(2) = 2 \times 3 - 1 \\ f(2) = 6 - 1 \\ f(2) = 5$

When n=2, we get:

$f(2+ 1) = 2f(2) - 1 \\ f(3) = 2 \times 5 - 1 \\ f(3) = 10 - 1 \\ f(3) = 9$

When n=3,

$f(3 + 1) = 2f(3) - 1 \\ f(4) = 2f(3) - 1 \\ f(4) = 2 \times 9 - 1 \\ f(4) = 18 - 1 \\ f(4) = 17$

When n=4

$f(4 + 1) = 2 f(4) - 1 \\ f(5) = 2 \times 17 - 1 \\ f(5) = 34 - 1 \\ f(5) = 33$

When n=5,

$f(6) = 65$

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3 years ago

Which complex number has a distance of radical 17 from the origin on the complex plane?

Inga [223]

Answer: LAST OPTION

Step-by-step explanation:

The complex numbers shown have the form:

$a+bi$

By definition, the distance can the distance of the complex number from the origin on the complex plane can be calculated with the formula shown below:

$d=\sqrt{a^2+b^2}$

Substitute values of each option. Then:

1) $d=\sqrt{2^2+15^2}=\sqrt{229}$

2) $d=\sqrt{17^2+1^2}=\sqrt{290}$

3) $d=\sqrt{20^2+(-3)^2}=\sqrt{409}$

4) $d=\sqrt{4^2+(-1)^2}=\sqrt{17}$ (CORRECT OPTION)

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3 years ago

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