If RS = 12 and ST = 7, find RT. U

: The perimeter of a rectangular garden is 46. The length is 7 less than 4 times the width. What are the dimensions of the garde

olga55 [171]

Let the width be x, then length = 4x - 7
Perimeter = 2(length + width)
2(x + 4x - 7) = 46
2(5x - 7) = 46
10x - 14 = 46
10x = 60
x = 6

Therefore, width is 6 and length is 4(6) - 7 = 24 - 7 = 17

4 0

3 years ago

Diego’s family car holds 14 gallons of fuel. Each day the car uses 0.6 gallons of fuel. A warning light comes on when the remain

Radda [10]

Answer:

14 gallons = 23 days

Step-by-step explanation:

14/6

6 0

3 years ago

The drama club at school sells $15.00

Elina [12.6K]

The profit on each book is $ 5.25

Solution:

Given that, the drama club at school sells $ 15.00 coupon books

Their profit is 35% of the total sales

Therefore,

Cost of a coupon book = $ 15

Profit = 35% of the total sales

We have to find the profit on each book

If a book is sold for $ 15 and then profit will be 35 % of 15

Let us find 35 % of 15

$Profit\ on\ each\ book = 35 \% \times 15\\\\Profit\ on\ each\ book = \frac{35}{100} \times 15\\\\Profit\ on\ each\ book = 0.35 \times 15\\\\Profit\ on\ each\ book = 5.25$

Thus profit on each book is $ 5.25

5 0

4 years ago

3х <9 How do I get the answer

Zigmanuir [339]

Answer:

beens they are 2 completely different things you would take and divide 9 by 3 to get 3 but you would not switch the sign because you are not dividing by a negative so the answer would be x < 3

7 0

3 years ago

Obtain or compute the following quantities.

iVinArrow [24]

Answer:

a) $F_{0.05,4,7}=0.16$

b) $F_{0.05,7,4}=0.24$

c) $F_{0.95,4,7}=4.12$

d) $F_{0.95,7,4}=6.09$

e) $F_{0.99,8,12}=4.50$

f) $F_{0.01,8,12}=0.18$

g) $P(F_{5,4} \leq 6.26)=0.95$

h) $P(0.177 \leq F_{10,5} \leq 4.74)=0.94$

Step-by-step explanation:

(a) F0.05, 4, 7 (Round your answer to two decimal places.)

For this case we need a valueof the F distribution with 4 degrees of freedom for the numerator and 7 for the denominator that accumulates 0.05 of the area on the left tail. We can use the following excel code: "=F.INV(0.05,4,7)". And we got:

$F_{0.05,4,7}=0.16$

(b) F0.05, 7, 4 (Round your answer to two decimal places.)

For this case we need a valueof the F distribution with 7 degrees of freedom for the numerator and 4 for the denominator that accumulates 0.05 of the area on the left tail. We can use the following excel code: "=F.INV(0.05,7,4)". And we got:

$F_{0.05,7,4}=0.24$

(c) F0.95, 4, 7 (Round your answer to three decimal places.)

For this case we need a valueof the F distribution with 4 degrees of freedom for the numerator and 7 for the denominator that accumulates 0.95 of the area on the left tail. We can use the following excel code: "=F.INV(0.95,4,7)". And we got:

$F_{0.95,4,7}=4.12$

(d) F0.95, 7, 4 (Round your answer to three decimal places.)

For this case we need a valueof the F distribution with 7 degrees of freedom for the numerator and 4 for the denominator that accumulates 0.95 of the area on the left tail. We can use the following excel code: "=F.INV(0.95,7,4)". And we got:

$F_{0.95,7,4}=6.09$

(e) the 99th percentile of the F distribution with v1 = 8, v2 = 12 (Round your answer to two decimal places.)

So for this case we need a value on the F distribution with 8 degrees of freedom for the numerator and 12 for the denominator that accumulates 0.99 of the area on the left tail. And we can use the following excel code: "=F.INV(0.99,8,12)". And we got:

$F_{0.99,8,12}=4.50$

(f) the 1st percentile of the F distribution with v1 = 8, v2 = 12 (Round your answer to three decimal places.)

So for this case we need a value on the F distribution with 8 degrees of freedom for the numerator and 12 for the denominator that accumulates 0.01 of the area on the left tail. And we can use the following excel code: "=F.INV(0.01,8,12)". And we got:

$F_{0.01,8,12}=0.18$

(g) P(F ≤ 6.26) for v1 = 5, v2 = 4 (Round your answer to two decimal places.)

For this case we want to find the probability that the F distribution with 5 degrees on the numerator and 4 on the denominator would be less or equal than 6.26. We can use the following excel code: "=F.DIST(6.26,5,4,TRUE)". And we got

$P(F_{5,4} \leq 6.26)=0.95$

(h) P(0.177 ≤ F ≤ 4.74) for v1 = 10, v2 = 5 (Round your answer to two decimal places.)

For this case we want to find the probability that the F distribution with 10 degrees on the numerator and 5 on the denominator would be between 0.177 and 4.74. We can use the following excel code: "=F.DIST(4.74,10,5,TRUE)-F.DIST(0.177,10,5,TRUE)". And we got

$P(0.177 \leq F_{10,5} \leq 4.74)=0.94$

3 0

3 years ago

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