You need the Law of Cosines here. Let's call our given angle A, so the side across from it, the one we are looking to solve for, would be a. The Law is as follows then: ![a^2=27^2+31^2-[2(27)(31)cos(75)]](https://tex.z-dn.net/?f=a%5E2%3D27%5E2%2B31%5E2-%5B2%2827%29%2831%29cos%2875%29%5D)
. We will simplify everything here at once to get 
. 
so a = 35.5
Plz help with both questions
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now we know the slope of line J is -1.
a line perpendicular to J, will have a negative reciprocal slope, therefore,
therefore, line K has a slope of 1, and passes through 3,4,