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2 years ago

14

A line contains the points (3, 8) and (6, 5). Write the equation of the line in slope-intercept form. Use no spaces in your equa

tion.

1 answer:

frez [133]2 years ago

6 0

Equation:
y = -x + 11

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Trigonometric Identity help

vovikov84 [41]

Answer:

sin $\pi$ /4 * sin $\pi$ /6 = 1/2 *(cos $\pi$ /12 - cos 5 $\pi$ /12)

Step-by-step explanation:

Formula:- sinX sinY = (1/2) [ cos (X - Y) - cos (X + Y) ]

sin(π/4)sin(π/6)

= (1/2)[cos(π/4 - π/6) - cos(π/4 + π/6)]

= (1/2)[cos(3π/12 - 2π/12) - cos(3π/12 + 2π/12)]

= (1/2)[cos(π/12) - cos(5π/12)]

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3 years ago

Find the absolute maximum and minimum values of the following function on the given interval. If there are multiple points in a

Bond [772]

$f(x)=3\sin x+3\cos x\implies f'(x)=3\cos x-3\sin x$

$f$ has critical points where $f'=0$ :

$3\cos x-3\sin x=0\implies\cos x=\sin x\implies\tan x=1\implies x=\pm\dfrac\pi4+2n\pi$

where $n$ is any integer. We get solutions in the interval $\left[0,\frac\pi3\right]$ for $n=0$ , for which $x=\frac\pi4$ .

At this critical point, we have $f\left(\frac\pi4\right)=3\sqrt2\approx4.243$ .

At the endpoints of the given interval, we have $f(0)=3$ and $f\left(\frac\pi3\right)=\frac{3+3\sqrt3}2\approx4.098$ .

So we have the extreme values

$\max\limits_{x\in\left[0,\frac\pi3\right]}f=3\sqrt2$

$\min\limits_{x\in\left[0,\frac\pi3\right]}f=3$

8 0

3 years ago

frutty [35]

1) add 7 to both sides and get -5....so -5 >x
2) add 7 to both sides.....so get b<-5
3) add 17 to both side...so get z>1

6 0

3 years ago

Read 2 more answers

Sonji has $5.25 in nickels and dimes.The coin value can be modeled by the equation 0.10 d plus 0.05 n equals 5.25, where d repre

Sedaia [141]

Answer:

Im not sure but i think it is 42

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

I WILL MARK YOU BRAINLYEST if you answer all of my problems !!!!!!!!!!!

Romashka [77]

First, let's convert each line to slope-intercept form to better see the slopes.

Isolate the y variable for each equation.

2x + 6y = -12

Subtract 2x from both sides.

6y = -12 - 2x

Divide both sides by 6.

y = -2 - 1/3x

Rearrange.

y = -1/3x - 2

Line b:

2y = 3x - 10

Divide both sides by 2.

y = 1.5x - 5

Line c:

3x - 2y = -4

Add 2y to both sides.

3x = -4 + 2y

Add 4 to both sides.

2y = 3x + 4

Divide both sides by 2.

y = 1.5x + 2

Now, let's compare our new equations:

Line a: y = -1/3x - 2

Line b: y = 1.5x - 5

Line c: y = 1.5x + 2

Now, the rule for parallel and perpendicular lines is as follows:

For two lines to be parallel, they must have equal slopes.

For two lines to be perpendicular, one must have the negative reciprocal of the other.

In this case, line b and c are parallel, and they have the same slope, but different y-intercepts.

However, none of the lines are perpendicular, as -1/3x is not the negative reciprocal of 1.5x, or 3/2x.

<h3><u>B and C are parallel, no perpendicular lines.</u></h3>

8 0

3 years ago