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NikAS [45]
3 years ago
8

What is the y-intercept of this line?​

Mathematics
2 answers:
denpristay [2]3 years ago
5 0

Answer:

y=mx+c or y=mx+b

gradient = rise/run

= 1 ( sloped upwards)

y= (1x)+c

y=x+c

to find c, we have to input values for x and y

take one point from the line on the graph, suppose...

(x,y) :  (-3,2)

2=-3+c

5=c

y=x+5

to solve for y, x will always be 0

y=0+5

y=5

Alex Ar [27]3 years ago
3 0

Answer:

5

Step-by-step explanation:

The Y intercept is where the line crosses the Y axis when X = 0.

(X,Y) -> (0, 5)

The equation of that line looks to be Y = X + 5.

That equation I wrote follows the Y = mx + B format.

The +B is the Y intercept.

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The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

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So mean height of the trees = (7+9+7+12+5)÷5

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Standard deviation of the trees at Yard works = ∑(║(height of the tree-mean height of the tree))║/(number of trees)

(height of the tree-mean height of the tree)= ║(7-8)║+║(9-8)║+║(7-8)║+║(12-8)║+║(5-8)║ = (1)+1+(1)+4+(3)= 10

Therefore standard deviation = (10)/(5) =2

2). In the same way mean height of the trees at Grow Station=(9+11+6+12+7)/5= 45/5 = 9

Now we will calculate the mean deviation of the tress at Grow Station

= ∑║(height of the tree-mean height of the tree)║/(number of trees)

= ║(9-9)║+║(11-9)║+║(6-9)║+║(12-9)║+║(7-9)║/(5)

= (0+2+3+3+2)/5

= 10/5 =2

Therefore The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

                                                             

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