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lorasvet [3.4K]
3 years ago
8

Successful Web sites such as StumbleUpon ( www.stumbleupon) and Digg ( www.digg) use ____ by inviting their visitors to vote on

recommended Web sites, articles, restaurants, photos, or videos, for example, by submitting links or reviews.
Computers and Technology
1 answer:
aliina [53]3 years ago
3 0

Answer:

"Crowdsourcing" is the correct answer for the above question.

Explanation:

  • Crowdsourcing is a term from which any organization advertises the thinks or can get the ideas or solutions for any particular problem.
  • It is a term that refers to the problem to the number of solvers to achieve the result correct and frequent.
  • For example, If anyone wants to prepare the two websites. Then he assigns the works to the number of people and the works done faster with the help of this.
  • The above question states that some websites can be successful with the help of the type of work. They are successful with the help of crowdsourced work. Because it saves time. So the answer is Crowdsourcing.
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//The Scanner class is imported to allow the program receive user input

import java.util.Scanner;

//The class Solution is defined

public class Solution {

   //The main method is defined here and signify the beginning of program execution

   public static void main(String args[]) {

       

       //Scanner object 'scan' is created to receive user input

       Scanner scan = new Scanner(System.in);

       //Prompt display to the user to enter size of array

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       //User input is assigned to arraySize

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       //userArray is initialized with arraySize as its size

       int[] userArray = new int[arraySize];

       

       //counter to count number of array element

       int count = 0;

       //while loop which continue executing till the user finish entering the array element

       while (count < arraySize){

           System.out.print("Enter each element of the array: ");

           userArray[count] = scan.nextInt();

           count++;

       }

       

       //A blank line is printed for clarity

       System.out.println();

       

       //for loop to print each element of the array on straight line

       for(int i =0; i <userArray.length; i++){

           System.out.print(userArray[i] + " ");

       }

       

       //A blank line is printed for clarity

       System.out.println();

       

       //for loop is use to reverse the array in-place

       for(int i=0; i<userArray.length/2; i++){

           int temp = userArray[i];

           userArray[i] = userArray[userArray.length -i -1];

           userArray[userArray.length -i -1] = temp;

       }

       

       //for loop to print each element of the reversed array on straight line

       for(int i =0; i <userArray.length; i++){

           System.out.print(userArray[i] + " ");

       }

     

   }

}

Explanation:

The program is commented to give detailed explanation.

The for-loop use in reversing the array works by first dividing the array into two half and exchanging the first half elements with the second half elements. The element from the first half is assigned to temp variable on each loop, then the element is replaced with the equivalent element from the second half. And the element from the second half is replaced with the value of temp.

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