Answer:
The correct answer to the following question will be "JAWS".
Explanation:
- JAWS is a strong accessibility tool, which uses synthesized speech to look for information on your monitor and provides several helpful commands to make it much easier using applications, edit documentation and read pages of the web.
- It's a Microsoft Windows screen reader tool that helps visually and blind impaired people to decode the screen either via a message-to-speech interpretation or with a castable sign language display.
- JAWS is manufactured by Freedom Scientific Blind and Group of Low Vision.
Therefore, JAWS is the right answer.
Answer:
6=110
13=1101
18=10010
27=11011
Explanation:
A decimal number is converted to binary number by constantly dividing the decimal number by 2 till the number becomes zero and then write the remainders in reverse order of obtaining them.Then we will get our binary number.
I will provide you 1 example:-
18/2 = 9 the remainder =0
9/2 = 4 the remainder =1
4/2 = 2 the remainder =0
2/2 = 1 the remainder =0
1/2 = 0 the remainder =1
Writing the remainder in reverse order 10010 hence it is the binary equivalent of 18.
Lexeme is a category or partitioned group of the small units of a programming language include its numeric literals, operators, and special words.
<h3>What is a lexeme in programming?</h3>
Lexemes are known to be those character strings that are put together from the character group of a program, and the token stands for what aspect of the program's grammar they are made of.
Hence, Lexeme is a category or partitioned group of the small units of a programming language include its numeric literals, operators, and special words.
Learn more about Lexeme from
brainly.com/question/14125370
#SPJ1
You should really state what language you are using. I have produced your method in C#, and should be easily translatable in to any other language.
static void RotateRight<T>(T[] arr)
{
T temp = arr[arr.Length - 1];
for (int i = arr.Length - 1; i >= 0; i--)
{
if (i == 0)
arr[i] = temp;
else
arr[i] = arr[i - 1];
}
}