Could you possibly tell me what exactly you need help with? As my computer already has viruses, I am surely not going to click on any of those. Sorry!
They might go extinct if they can't keep up with the competition
Answer:
B) The mass of the reactants equals the mass of the products,
Explanation:
Given that the reaction is balanced, the mass of the reactants must equal to the mass of the products.
We know this by virtue of the law of conservation of mass.
The law of conservation of mass states that "in a chemical reaction, matter is neither created nor destroyed but atoms are rearranged".
Therefore, if the reaction is chemically balanced, the mass of reactants must be the same as the mass of the products in the reaction.
The second choice is the right one.
It is called central vascular catheterization
<h3>Importance of catheterization</h3>
Catheterization is defined as the use of medical devices that can be inserted into the body and used for different medical purposes.
Vascular catheterization is a peripheral catheterization that is used to detect certain upper and lower peripheral extremity conditions.
There are different types of vascular catheterization which include:
- Arteriovenous (AV) fistula,
- Arteriovenous (AV) graft and
- Central venous catheter (CVC)
Central vascular catheterization involves Introducing a vascular catheter directly into a vessel without further advancement past the punctured vessel.
Learn more about catheterization here:
brainly.com/question/3911876
Answer:
8.800s
Explanation:
When the performer swings, she oscillates in SHM about Lo of the string with time period To = 8.90s.
First, determine the original length Lo, where for a SHM the time period is related to length and the gravitational acceleration by the equation
T = 2π×√(Lo/g)..... (1)
Let's make Lo the subject of the formulae
Lo = gTo^2/4π^2 ..... (2)
Let's put our values into equation (2) to get Lo
Lo = gTo^2/4π^2
= (9.8m/s^2)(8.90s)^2
------------------------------
4π^2
= 19.663m
Second instant, when she rise by 44.0cm, so the length Lo will be reduced by 44.0cm and the final length will be
L = Lo - (0.44m)
= 19.663m - 0.44m
= 19.223m
Now let use the value of L into equation (1) to get the period T after raising
T = 2π×√(L/g)
= 2π×√(19.223m/9.8m/s^2)
= 8.800s
