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3 years ago

What is a resonable estimate for 5,897 ?

Mathematics

1 answer:

Romashka-Z-Leto [24]3 years ago

7 0

Yeah its 5,900
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W/3 =9 <br> what is w ? W=____

RUDIKE [14]

Answer:

Step-by-step explanation:

27÷3 = 9

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4 years ago

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Several terms of a sequence {an}n=1 infinity are given. A. Find the next two terms of the sequence. B. Find a recurrence relatio

s344n2d4d5 [400]

Answer:

A) $\frac{1}{1024},\frac{1}{4096}$

B) $\left\{\begin{matrix}a(1)=1 & \\ a(n)=a(n-1)*\frac{1}{4} &\:for\:n=1,2,3,4,... \end{matrix}\right.$

C) $\\a_{n}=nq^{n-1} \:for\:n=1,2,3,4,...$

Step-by-step explanation:

1) Incomplete question. So completing the several terms: $\left \{a_{n}\right \}_{n=1}^{\infty}=\left \{ 1,\frac{1}{4},\frac{1}{16},\frac{1}{64},\frac{1}{256},... \right \}$

We can realize this a Geometric sequence, with the ratio equal to:

$q=\frac{1}{4}$

A) To find the next two terms of this sequence, simply follow multiplying the 5th term by the ratio (q):

$\frac{1}{256}*\mathbf{\frac{1}{4}}=\frac{1}{1024}\\\\\frac{1}{1024}*\mathbf{\frac{1}{4}}=\frac{1}{4096}\\\\\left \{ 1,\frac{1}{4},\frac{1}{16},\frac{1}{64},\frac{1}{256},\mathbf{\frac{1}{1024},\frac{1}{4096}}\right \}$

B) To find a recurrence a relation, is to write it a function based on the last value. So that, the function relates to the last value.

$\left\{\begin{matrix}a(1)=1 & \\ a(n)=a(n-1)*\frac{1}{4} &\:for\:n=1,2,3,4,... \end{matrix}\right.$

C) The explicit formula, is one valid for any value since we have the first one to find any term of the Geometric Sequence, therefore:

$\\a_{n}=nq^{n-1} \:for\:n=1,2,3,4,...$

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3 years ago

A baby weighing 7 pounds at birth increases weight in by 11% per month for the first 12 months how much will the baby weigh afte

AlexFokin [52]

idk but I neeeed Helppp!!!

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3 years ago

Help on functions please.

dedylja [7]

A) Sub g(x) and h(x) into the equation:
x^2 + 3x - 40 - (-x -3)
= x^2 + 3x - 40 +x + 3
= x^2 + 4x - 37
Find x:
x= 4.40 and x= -8.40
b) Sub f(x) and g(x) into the equation:
(x^2 - 64) / (x^2 + 3x -40)
= ((x+8) x (x-8)) / ((x+8) x (x-5))
= (x - 8) / (x-5)
Find x:
x= 8 and x = 5
How to get those number:
(x^2 - 64) = x^2 - 8^2 = (x-8) x (x+8)
( x^2 + 3x - 40) = (x^2 + +8x - 5x - 40) = x( x + 8) - 5( x + 8) = (x-5) x (x+8)

Try to do c and d :)

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4 years ago

Identify the number that does not belong with the other three. Explain your reasoning. 50.1 repeating 1, negative 50 over 2, neg

ivolga24 [154]

50.1 repeateding because that is the only positive number

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3 years ago

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