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Arada [10]
2 years ago
9

Eliana drove her car 81 km, space, k, m and used 9 liters of fuel. She wants to know how many kilometers(x) she can drive on 22

liters of fuel. She assumes her car will continue consuming fuel at the same rate. How far can Eliana drive on 222222 liters of fuel?
Mathematics
1 answer:
olya-2409 [2.1K]2 years ago
8 0

Question: Eliana drove her car 81 km, space, k, m and used 9 liters of fuel. She wants to know how many kilometers(x) she can drive on 22 liters of fuel. She assumes her car will continue consuming fuel at the same rate. How far can Eliana drive on 222222 liters of fuel?

Answer: Eliana can drive on 22 liters of fuel and can drive up to 198 km

Explanation: 9 liters = 81km so 81 divided by 9  so now it becomes 1 liter =9km  22 liters so 22x9 = 198km

question answered by

(jacemorris04)

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Suppose GDP is $12 trillion, taxes are $3.6 trillion, private saving is $1.5 trillion, and public saving is $0.8 trillion. Assum
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Assuming this economy is closed: Consumption $6.9 trillion; Government Purchases $11.2 trillion; National Saving $2.3 trillion; Investment $2.3 trillion.

<h3>Gross domestic product</h3>

a. Consumption

Private S = ( Y – T – C )

C = Y - T - Private S

C = $12 - $3.6 - $1.5 =$6.9 trillion

b. Government purchases

Public S = ( T - G )          

G = T - Public S                                                        

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3 0
2 years ago
se necesita llenar un galon de agua,en 2 litros se tarda 30 minutos.cuantos litros me hacen falta para completar el galon y cual
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Answer: 1.78 L are needed to complete the gallon and it will take 29.66 min to completely fill it

Step-by-step explanation:

The question in english is:

A gallon of water needs to be filled, in 2 liters it takes 30 minutes. How many liters do I need to complete the gallon and what is the time it takes me to fill it?

We know 1 gallon is equal to 3.78 liters:

1 gal=3.78 L

In addition, we are told you have filled the gallon with 2 L at a rate of \frac{2 L}{30 min}=0.06 L/min.

So, if we want to know how many liters are left to completely fill the gallon, we have to sbstract the 2 L to the total amount of a gallon:

3.78 L-2 L=1.78 L This is the amount you need to complete the gallon

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rate=\frac{Liters}{time}

Isolating time:

time=\frac{Liters}{rate}

Then, if we input the 1.78 L we need to fill the gallon we will have the time:

time=\frac{1.78 L}{0.06 L/min}

time=29.66 min This is the time you need to fill the gallon

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