Question

How to find the permimeter of triangle ABC with the vertices of A(1,1) B(7,1) C(1,9)

Answer 1

Answer:

Perimeter of the triangle=24 units

Step-by-step explanation:

The given vertices of the triangle ABC are A(1,1), B(7,1) and C(1,9).In order to fin the perimeter, we need to find the lengths of the triangle.

Thus, AB=$\sqrt{(7-1)^{2}+(1-1)^{2}}=\sqrt{36}=6$,

BC=$\sqrt{(1-7)^{2}+(9-1)^{2}}=\sqrt{36+64}=\sqrt{100}=10$ and

AC=$\sqrt{(1-1)^{2}+(9-1)^{2}}=\sqrt{64}=8$

Now, Perimeter of the triangle= Sum of all the sides

=AB+BC+AC

=6+10+8

=24 units.

Thus, Perimeter of the triangle=24 units