Answer:
it is true. any whole number has a 0 following the decimal
Let's solve this problem step-by-step.
−3(1−2x)=3x+3(x−3)+6
Step 1: Simplify both sides of the equation.
−3(1−2x)=3x+3(x−3)+6
(−3)(1)+(−3)(−2x)=3x+(3)(x)+(3)(−3)+6(Distribute)
−3+6x=3x+3x+−9+6
6x−3=(3x+3x)+(−9+6)(Combine Like Terms)
6x−3=6x+−3
6x−3=6x−3
Step 2: Subtract 6x from both sides.
6x−3−6x=6x−3−6x
−3=−3
Step 3: Add 3 to both sides.
−3+3=−3+3
0=0
So, 0=0 or all real numbers.
Answer:
Step-by-step explanation:
-1 > -2(x-4) - 5(4x - 7)
-1 > -2x + 8 - 20x + 35
-1 > -22x + 43
-1 - 43 > - 22x
-44 > - 22x
-44/-22 < x
2 < x....or x > 2
Funtion ! in vertex form is given by
<span>f(x) = 4x^2 + 8x + 1</span> = 4(x^2 + 2x + 1/4) = 4(x^2 + 2x + 1 + 1/4 - 1) = 4(x + 1)^2 + 4(-3/4) = 4(x + 1)^2 - 3
Thus, the least minimun value is (-1, -3)
Also, the least minimum value of function 2 is (-1, 0)
Therefore, function 1 has the least minimum value at (-1, -3)
