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vovikov84 [41]
4 years ago
8

A sample of size n = 12 does not have a known population standard deviation. The population appears to be normally distributed.

Determine whether a margin of error should be calculated using a critical value of zα/2, a critical value of tα/2, or neither.
a critical value of tα/2


neither


a critical value of zα/2
Mathematics
1 answer:
8090 [49]4 years ago
7 0

420

.,...................................

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N employee earns $175 for 15 hours work. assuming he is paid by the hour, how much will this employee earn in 18 hours?
alekssr [168]
First you would divide 175 by 15 and get 11.6666666667, you would then multiply that by 18 amd get 210.0000000001
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3 years ago
The diagram shows the distance between my home, H. and two towns, A and B.
olga nikolaevna [1]

I do not know English :33333

7 0
3 years ago
3
nikitadnepr [17]

Answer:

y = (1/4)x - 3

Step-by-step explanation:

The slope-intercept form is y = mx + b.  Here we are told that the line passes through (-8, -5) and that its slope is 1/4 (is that correct?).  

Substituting -5 for y, -8 for x and 1/4 for m, we get an equation for the y-intercept, b:

-5 = (1/4)(-8) + b, or

-5 = -2 + b, so b = -3, and the desired equation is

y = (1/4)x - 3

3 0
3 years ago
Company A makes a large shipment to Company B. Company B can reject the shipment if they can conclude that the proportion of def
boyakko [2]

Answer:

z=\frac{0.1475-0.1}{\sqrt{\frac{0.1(1-0.1)}{400}}}=3.17  

The p value for this case would be given by:

p_v =P(z>3.17)=0.00076  

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 0.1 and then Company B can reject the shipment

Step-by-step explanation:

Information provided

n=400 represent the random sample taken

X=59 represent number of defectives from the company B

\hat p=\frac{59}{400}=0.1475 estimated proportion of defectives from the company B  

p_o=0.1 is the value to verify

\alpha=0.05 represent the significance level

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to verify if the true proportion of defectives is higher than 0.1 then the system of hypothesis are.:  

Null hypothesis:p \leq 0.1  

Alternative hypothesis:p > 0.1  

The statistic would be given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info given we got:

z=\frac{0.1475-0.1}{\sqrt{\frac{0.1(1-0.1)}{400}}}=3.17  

The p value for this case would be given by:

p_v =P(z>3.17)=0.00076  

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 0.1 and then Company B can reject the shipment

8 0
4 years ago
What is the solution to this inequality?<br> -4X &gt; 500
Tcecarenko [31]

Answer: x < -125

Step-by-step explanation:

-4x / (-4) < 500 / (-4)

x < -125

7 0
4 years ago
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