First find the amount of increase: 380-300=80. Then divide the amount of increase by the original amount: 80/300=.266666667. Normally you round to the tenths place: .27. Then make it a percent: .27=27%. The percent of increase is 27% :) hope this helps
Answer:
125
Step-by-step explanation:
Steps to Solving the Problem
So let's say you have five friends who who are each going to pay you five dollars for the next five days. You can figure out how much money you will receive by calculating five cubed or five to the third power. This will tell us how much money you will get because you will multiply 5 by 5 by 5 or 5 cubed.
To start, you need to turn words into numbers by figuring out the base and exponent. An exponent is the number after the ^ which tells you how many times to multiply the base number by itself. The base number comes before the ^. When five is cubed, five is the base number which will show up before the ^.
Three is the exponent and will be the number after the ^. We know three is the exponent because of the word 'cubed,' which always represents the number three.
We can write out five cubed as:
5^3
Once the exponent and base are figured out, we need to write out the long version, which shows all the multiplication being done. In this case, the exponent of three tells us to multiply five by itself three times.
5 x 5 x 5
This shows us 5 friends multiplied by $5 multiplied by 5 days.
From here, multiply the numbers out to get the final answer. Multiply two numbers at a time to so you don't make a mistake.
5 x 5 = 25
25 x 5 = 125
Answer:
2..25
Step-by-step explanation:
Answer:
A) C1 = 0.00187 m = 0.187 cm, C2 = 0.0062 m = 0.62 cm
B) A sample of how the graph looks like is attached below ( periodic sine wave )
C) w = ![\sqrt[4]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B3%7D)
is when the amplitude of the forced response is maximum
Step-by-step explanation:
Given data :
mass = 5kg
length of spring = 10 cm = 0.1 m
f(t) = 10sin(t) N
viscous force = 2 N
speed of mass = 4 cm/s = 0.04 m/s
initial velocity = 3 cm/s = 0.03 m/s
Formulating initial value problem
y = viscous force / speed = 2 N / 0.04 m/s = 50 N sec/m
spring constant = mg/ Length of spring = (5 * 9.8) / 0.1 = 490 N/m
f(t) = 10sin(t/2) N
using the initial conditions of u(0) = 0 m and u"(0) = 0.03 m/s to express the equation of motion
the equation of motion = 5u" + 50u' + 490u = 10sin(t/2)
A) finding the solution of the initial value
attached below is the solution and
B) attached is a periodic sine wave replica of how the grapgh of the steady state solution looks like
C attached below
