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3 years ago

If the area of the blue square is 25 in2 and the area of the green square is 15 points

Mathematics

1 answer:

galben [10]3 years ago

6 0

Answer:

144 in²

Step-by-step explanation:

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Complete the point slope equation of the lone through (-8,-1) and (-6,5)

sweet-ann [11.9K]

Answer:

slope m = (5+1)/(-6+8) = 6/2 =3

5 0

3 years ago

Suppose compact fluorescent light bulbs last, on average, 11,500 hours. The distribution is normal and the standard deviation is

juin [17]

Answer:

2.275%

Step-by-step explanation:

The first thing to do here is to calculate the z-score

Mathematically;

z-score = (x-mean)/SD

from the question, x = 12,300 hours , mean = 11,500 hours while Standard deviation(SD) = 400 hours

Plugging the values we have;

z-score = (12,300-11,500)/400 = 800/400 = 2

Now, we want to calculate P(z ≤ 2)

This is so because we are calculating within a particular value

To calculate this, we use the z-score table.

Mathematically;

P(z ≤ 2) = 1 - P(z > 2) = 1 - 0.97725 = 0.02275

To percentage = 2.275%

6 0

3 years ago

Solve for the value of x.

choli [55]

Answer:

Step-by-step explanation: I just guessed

3 0

2 years ago

Read 2 more answers

Can you help me to solve this

Ber [7]

Answer:

$\frac{4a-2}{2a+1}$

Step-by-step explanation:

Factorise the numerator and denominator

8a² - 2 ← factor out 2 from each term

= 2(4a² - 1) ← 4a² - 1 is a difference of squares

= 2(2a - 1)(2a + 1)

4a² + 4a + 1 ← is a perfect square

= (2a + 1)²

Thus

$\frac{8a^2-2}{4a^2+4a+1}$

= $\frac{2(2a-1)(2a+1)}{(2a+1)(2a+1)}$ ← cancel (2a + 1) on numerator/ denominator

= $\frac{2(2a-1)}{2a+1}$

= $\frac{4a-2}{2a+1}$

3 0

3 years ago

Read 2 more answers

What goes where. JdhshshHshxjancixd

valentina_108 [34]

Answer:

$\boxed { \frac{7}{5}y } \to \: \boxed {y+ \frac{2}{5}y }$

$\boxed { \frac{3}{5}y } \to \: \boxed {y - \frac{2}{5}y }$

Step-by-step explanation:

We need to simplify

$y + \frac{2}{5}y$

We collect LCM to get;

$\frac{5y + 2y}{5} = \frac{7y}{5}$

Therefore:

$\boxed { \frac{7}{5}y } \to \: \boxed {y+ \frac{2}{5}y }$

Also we need to simplify:

$y - \frac{2}{5}y$

We collect LCM to get;

$y - \frac{2}{5}y = \frac{5y - 2y}{5} = \frac{3}{5} y$

Therefore

$\boxed { \frac{3}{5}y } \to \: \boxed {y - \frac{2}{5}y }$

5 0

3 years ago