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ad-work [718]
3 years ago
6

Given the functions j(x) = x2 − 9 and k(x) = −x2 + 7x − 1, which operation results in a 3rd degree polynomial?

Mathematics
1 answer:
Effectus [21]3 years ago
8 0
1.] multiplication of x squared by x yields a 3rd degree polynomial (having an x cubed term) 

<span>2.] (x+3)^1/2 - 4 = x - 1 </span>
<span>(x+3)^1/2 = x + 3 </span>
<span>square both sides: x+3 = (x+3)^2 </span>
<span>simplify: x + 3 = x^2 + 6x + 9 </span>
<span>bring all terms to one side so that 0 = x^2 + 5x + 6 </span>
<span>factor the polynomial 0 = (x + 2) ( x + 3) </span>
<span>set each factor equal to zero & solve to get x = -2 and x = -3 </span>

<span>3.] x = 4 , not extraneous </span>

<span>4.] In mathematics, complex conjugates are a pair of complex numbers, both having the same real part, but with imaginary parts of equal magnitude and opposite signs. So -6 - 5i and -6 + 5i are complex conjugates. </span>

<span>5.] x = 8 and x = 9 </span>

<span>6.] x to the sixteenth twenty fifth power </span>
<span>x^4/5 * x^4/5 multiply exponents to get x^16/25 </span>

<span>7.] quantity of 80 minus 50 i over 39</span>
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