U can use the Pythagorean theorem which is (a^2 + b^2 = c^2) It'll help you a lot
- Given - <u>a </u><u>rectangle </u><u>with </u><u>length</u><u> </u><u>2</u><u>5</u><u> </u><u>feet </u><u>and </u><u>perimeter </u><u>8</u><u>0</u><u> </u><u>feet</u>
- To calculate - <u>width </u><u>of </u><u>the </u><u>rectangle</u>
We know that ,
where <u>b </u><u>=</u><u> </u><u>width </u><u>/</u><u> </u><u>breadth</u> of rectangle
<u>substituting</u><u> </u><u>the </u><u>values </u><u>in </u><u>the </u><u>formula </u><u>stated </u><u>above </u><u>,</u>
hope helpful ~
Supplementary angles add up to 180°
-> The measure of an angle that is supplementary to a 71° angle is 180° - 71° = 129°
Ans: 1.1 miles more
Speed = distance/time
Time is 1/5 of an hour
1/5 of 1hr = 1/5 or 0.2 hrs
Speed = 16 mph
So, we're after distance.
Distance = speed x time
= 16mph x 0.2
= 3.2 miles
Walks for 3/7 hour at 5 miles per hour :
Time & speed given, distance is what we're after.
(3/7 of 1hr is 3/7)
Distance = speed x time
= 5mph x 3/7
= 15/7 miles or 2.14285...miles
So, distance is about 2.1 miles to 1 d.p
Thus, 3.2 - 2.142... (the full ans) = 1.057... miles
Well, he biked 1.06 miles or 1.1 miles (depending on how you want to round it) more than walking.
Hope this helps!
