Answer:
2
Explanation:
It will help them to learn English better- then they can use their other language at home
Other assumptions associated with this question are as follows:
- One person can feed on 1 hen/day for a year
- 1 hen must east 25 grasshoppers /day
- the total mass of 1000 grasshoppers is 1kg
- 600 grasshoppers are needed to feed 1 human per day
Grasshoppers is represented as Gh.
The total amount needed to feed the hen per year is:
- If expressed in Kg, then it would be 9,125/1000 which is
- = 9.125Kg/annum.
So if the farmer chose to live on grasshoppers rather than on hens, the calculation is given as follows:
- (90 kg/1 hour) x (24 hours/1 day) x (1 person/ 600 Gh)
The amount of Grasshoppers required is given as follows;
If the farmer can gather 90 Gh in one hour then,
- The total amount of Gh per day is 90 x 24 = 2,160
- the total amount of Gh available in a year is 2160 x 365 = 788,400 Gh/Year
- If 600 grasshoppers are quired to feed the human per day, then we work backward
- The total amount of Gh available in a day is 788,400/365. This is equal to 2160 Gh
- The total amount of people this can feed is given as 2,160/600
- Which is equal to 3.6 persons.
Since humans or people cannot be divided into fractions like a measure of sugar or a measure of liquid, the answer is best left to the most approximate digit with it 4 Persons.
Learn more about Trophic Levels and food availability here:
brainly.com/question/2001301
Supply and demand! The prices will rise until the supply will reach the demand.
Answer:
1.5x10^10 KWh
Explanation:
Data obtained from the question include:
Power (P) = 3GW
We need to convert 3 gigawatts (GW) to Kilowatts (KW) in order to obtain the desired result. This is illustrated below:
1 GW = 1x10^6 KW
Therefore, 3 GW = 3x10^6 KW
Time (t) = 5000 hrs/yr
Energy (E) =?
Power is simply the amount of energy transferred per unit time. It can be expressed mathematically as:
Power (P) = Energy (E) / Time (t)
P = E/t
Applying the above formula, we can calculate the energy in kWh of electricity that can be produced by the plant in one year. This is illustrated below:
P = E/t
3x10^6 KW = E / 5000 hrs/yr
Cross multiply to express in linear form as shown below:
E = 3x10^6 KW x 5000 hrs/yr
E = 1.5x10^10 KWh
Therefore, 1.5x10^10 KWh of electricity can be produced by the plant in one year.
