Probability is expressed as
number of favourable outcomes/total number of possible outcomes
Looking at the given scenario, the number os students that earned a grade of A is 5. Since we are concerned with these students, then, the number of favourable outcomes is 5.
The total number of students for all grades is 35. This means that the total number of possible outcomes is 35
Thus, the probability that a student earns a grade of A is
5/35
= 0.14
Answer:
c,d
Step-by-step explanation:
![ab^{-3x}=a(b^{-3})^x=a(\frac{1}{b^3} )^x=a[(\frac{1}{b} )^3]^x\\=a(\frac{1}{b} )^{3x}](https://tex.z-dn.net/?f=ab%5E%7B-3x%7D%3Da%28b%5E%7B-3%7D%29%5Ex%3Da%28%5Cfrac%7B1%7D%7Bb%5E3%7D%20%29%5Ex%3Da%5B%28%5Cfrac%7B1%7D%7Bb%7D%20%29%5E3%5D%5Ex%5C%5C%3Da%28%5Cfrac%7B1%7D%7Bb%7D%20%29%5E%7B3x%7D)
Answer: The total number of colored papers is 18.
Step-by-step explanation:
Given: The ratio of coloured papers to wight papers is 3:8.
Let total number of colored papers = 3x
and total number of wight papers = 8x
Since, there are 48 wight papers , then


Now , number of colored papers = 3(6)=18
Hence, the total number of colored papers is 18.
Answer:
∴ Constant of Proportionality is 32
Step-by-step explanation:
Here Given;
(equation-1)
(equation-2) (divide with 'g' on both side)
We know,
The Constant of Proportionality equation is given;
(equation-3)
Where 'k' is known as Constant of Proportionality.
Comparing equation-1 and equation-3;
and 
Now equation-2 become;

Plug
and
in above equation;
(equation-4)
By comparing equation-2 and equation-4;

So Constant of Proportionality is 32