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Dimas [21]
3 years ago
8

20 points! I would really like some help! :) (Question attached below)

Mathematics
1 answer:
snow_lady [41]3 years ago
4 0

Answer:

See below.

Step-by-step explanation:

(a)

To multiply two polynomials, multiply every term of the first polynomial by every term of the second polynomial. Then combine like terms.

(\dfrac{1}{2}x - \dfrac{1}{4})(5x^2 - 2x + 6) =

= \dfrac{1}{2}x \times 5x^2 - \dfrac{1}{2}x \times 2x + \dfrac{1}{2}x \times 6 - \dfrac{1}{4} \times 5x^2 + \dfrac{1}{4} \times 2x - \dfrac{1}{4} \times 6

= \dfrac{5}{2}x^3 - x^2 + 3x - \dfrac{5}{4}x^2 + \dfrac{1}{2}x - \dfrac{3}{2}

= \dfrac{5}{2}x^3 - \dfrac{9}{4}x^2 + \dfrac{7}{2}x - \dfrac{3}{2}

(b)

No. Since the binomials are different, the product of two different binomials and the same trinomial will give different results.

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lesya692 [45]

The values of a, b, and c in given quadratic equation are:

a = 6 and b = -9 and c = 7

<em><u>Solution:</u></em>

Given quadratic equation is:

-6x^2 = -9x + 7

Let us first convert the given quadratic equation to standard form

The standard form is ax^2+bx+c=0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable

-6x^2 = -9x + 7\\\\-6x^2+9x-7=0\\\\6x^2-9x+7=0

Now we have to find the values of a, b, c

\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Thus comparing 6x^2-9x+7=0 with standard form of quadratic equation a x^{2}+b x+c=0

a = 6

b = -9

c = 7

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4 years ago
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lakkis [162]

Answer:

The given point A (6,13) lies on the equation.  True

The given point  B(21,33) lies on the equation.  True

The given point  C (99, 137) lies on the equation.  True

Step-by-step explanation:

Here, the given equation is : y =\frac{4}{3} x + 5

Now,check the given equation for the given points.

1)  A (6,13)

Substitute x = 6 in the given equationy =\frac{4}{3} x + 5

y =\frac{4}{3} (6) + 5  = 4(2) + 5  = 8 + 5 =  13

⇒ y= 13

Hence, the given point A (6,13) lies on the equation.

2)  B  (21,33)

Substitute x = 21 in the given equationy =\frac{4}{3} x + 5

y =\frac{4}{3} (21) + 5  = 4(7) + 5  = 28 + 5 =  33

⇒ y  = 33

Hence, the given point  B(21,33) lies on the equation.

3)  C (99, 137)

Substitute x = 99 in the given equationy =\frac{4}{3} x + 5

y =\frac{4}{3} (99) + 5  = 4(33) + 5  = 132 + 5 =  137

⇒ y  = 137

Hence, the given point  C (99, 137) lies on the equation.

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Answer:

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Step-by-step explanation:

we know that

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Other method:
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