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attashe74 [19]
3 years ago
6

PLZ HELP WILL GIVE BRAINLIEST AND 20 POINTS

Mathematics
1 answer:
kompoz [17]3 years ago
3 0
Your answer is 80. your answer

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This thing mad hard for no reason
muminat

Answer:

1. 3.81 x 10^2

2. 2.571428 × 10^1

3. 5x10^2

4.  1.09 x 10^-6

5. 2x10^-5

Step-by-step explanation:

Make sure to put a line over the numbers that have decimals.

4 0
2 years ago
Read 2 more answers
17+17+17+17+17+1764638292836362729=
Mazyrski [523]

Answer:

1.7646383e+18

Step-by-step explanation:

mark me as brainliest pls :)

8 0
3 years ago
Read 2 more answers
A field is shaped like the figure shown. What is the area of the field? Use 3.14
uysha [10]
There is no figure, i cant help you sorry
6 0
3 years ago
1. h(2) + g(2) *<br> h(t) = 3-5<br> g(t) = 2t - 5
kap26 [50]

Answer:

h(2)+g(2) = -3

Step-by-step explanation:

h(2) +g(2)\\ \\h(t) = 3-5, g(t) = 2t -5

        Replace the variable  (t)  with (

2)  in the expression.

h (2) = 3 - 5

        Replace the variable  (t)  with (

2)  in the expression.

g(2) = 2(2) -5

        Replace the function designators in h(2) +g(2) with the actual functions.

h(t) = 3 - 5 +2 (2) ← plug h(2) into 2(t)

         Remove parentheses.

3 - 5 + 2(2)

         Multiply 2 by 2

3 - 5 + 4 - 5

         Subtract  5  from  3

.

-2 + 4 - 5

          Add -2 and 4

2 - 5

          Subtract 5 from 2

-3

7 0
3 years ago
A machine, when working properly, produces 5% or less defective items. Whenever the machine produces significantly greater than
vovikov84 [41]

Answer:

The pvalue of the test is 0.0007 < 0.01, which means that we reject the null hypothesis and accept the alternate hypothesis that the percentage of defective items produced by this machine is greater than 5%.

Step-by-step explanation:

A machine, when working properly, produces 5% or less defective items.

This means that the null hypothesis is:

H_0: p \leq 0.05

Test if the percentage of defective items produced by this machine is greater than 5%.

This means that the alternate hypothesis is:

H_a: p > 0.05

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.05 is tested at the null hypothesis:

This means that \mu = 0.05, \sigma = \sqrt{0.05*0.95}

A random sample of 300 items taken from the production line contained 27 defective items.

This means that n = 300, X = \frac{27}{300} = 0.09

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.09 - 0.05}{\frac{\sqrt{0.05*0.95}}{\sqrt{300}}}

z = 3.18

Pvalue of the test:

Testing if the mean is greater than a value, which means that the pvalue of the test is 1 subtracted by the pvalue of Z = 3.18, which is the probability of a finding a sample proportion of 0.09 or higher.

Looking at the Z-table, Z = 3.18 has a pvalue of 0.9993

1 - 0.9993 = 0.0007

The pvalue of the test is 0.0007 < 0.01, which means that we reject the null hypothesis and accept the alternate hypothesis that the percentage of defective items produced by this machine is greater than 5%.

5 0
3 years ago
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