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stealth61 [152]
4 years ago
10

You open a savings account with a $50.00 deposit. You make a deposit of $20.00 and two more of $35.00 each and 2 withdrawals of

$10.00 each. Which of the following is an expression of the amount in your account after these transaction?
$50.00+$20.00- 2($35.00) +2 ($10.00) = $20.00

$20.00+2($35.00) -2 ($10.00) = $70.00

$50.00+$20.00+2($35.00) -2 ($10.00) = $120.00

$50.00+$20.00+2($35.00) +2 ($10.00) = $140.00
Mathematics
2 answers:
OLga [1]4 years ago
6 0
I believe the answer is C
kotykmax [81]4 years ago
3 0
A deposit is an addition and a withdrawal is a subtraction, so:
50.00 + 20.00 + 2(35.00) - 2(10)

Letter C:)
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The difference between a number and five equals three. Translate this sentence to an equation and then find the number .
MAXImum [283]
Let:
x = Desired Number
The information put into numbers would look like this:
x - 5 = 3
All we have to do is add 5 to both sides to get x on its own on the left and a single number on the right side, so:
x = 3 + 5
x = 8
5 0
3 years ago
Read 2 more answers
The points (4, 1) and (x, -6) lie on the same line. If the slope of the line is 1 what is the value of x?
Nana76 [90]

Answer:

The value of x is -3

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of a line that passes through points (x1 , y1) and (x2 , y2) is

  m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

* Lets solve the problem

∵ The points (4 , 1) and (x , -6) lie on the same line

∵ The slope of the line is 1

- Let the point (4 , 1) is (x1 , y1) and the point (x , -6) ix (x2 , y2)

∵ x1 = 4 , x2 = x and y1 = 1 , y2 = -6

∴ m=\frac{x-4}{-6-1}

∴ m=\frac{x-4}{-7}

∵ The slope of the line is m = 1

∴ \frac{x-4}{-7}=1

- By using cross multiplication

∴ x - 4 = -7 ⇒ add 4 to both sides

∴ x = -3

* The value of x is -3

4 0
3 years ago
What is the definition of input
notka56 [123]
The definition of input is What is put in, taken in, or operated on by any process or system so the data put into a computer, calculator, math problem is the input
5 0
3 years ago
Find the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the pop
Andreyy89

Answer:

The smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income is 48.

Step-by-step explanation:

The complete question is:

The mean salary of people living in a certain city is $37,500 with a standard deviation of $2,103. A sample of n people will be selected at random from those living in the city. Find the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income. Round your answer up to the next largest whole number.

Solution:

The (1 - <em>α</em>)% confidence interval for population mean is:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

The margin of error for this interval is:

MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

The critical value of <em>z</em> for 90% confidence level is:

<em>z</em> = 1.645

Compute the required sample size as follows:

MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

      n=[\frac{z_{\alpha/2}\cdot\sigma}{MOE}]^{2}\\\\=[\frac{1.645\times 2103}{500}]^{2}\\\\=47.8707620769\\\\\approx 48

Thus, the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income is 48.

3 0
3 years ago
Given right triangle A w/a hypotenuse length of 3y + x and a leg of y-x, and right triangle B, w/ a hypotense length of y+5 and
Darya [45]
We use the law of correspondence that is 
Hypotenuse = Hypotenuse Leg = Leg 

3y + x = y + 5 
and 
y - x = x + 5 --------------------------------- work on your first problem to find x 
x = -2y + 5 
now you can plug this in to your second equation to sub in for the x 
y - ( -2y + 5 ) = ( -2y + 5 ) + 5 y + 2y - 5 = -2y + 10 3y - 5 = -2y + 10 5y = 15 y = 3 
Now you can plug back in to solve for x 

3y + x = y + 5 3(3) + x = (3) + 5 9 + x = 8 x = -1 
so y = 3 and x = -1
4 0
3 years ago
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