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3 years ago

-5/8x+2>56/16 please help anything will do

Mathematics

1 answer:

Zolol [24]3 years ago

8 0

Answer:

x<−12/5

Step-by-step explanation:

I hope this help you

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Evaluate the integral using integration by parts with the indicated choices of u and dv. (Use C for the constant of integration.

trasher [3.6K]

Answer:

$\frac{xe^{7x}}{7} + \frac{e^{7x}}{49}$

Step-by-step explanation:

Given the integral equation

$\int\limits{xe^{7x}} \, dx \\$

According to integration by part;

$\int\limits {u} \, dv = uv + \int\limits {v} \, du$

u = x, dv = e^7x

du/dx = 1

du = dx

$v = \int\limits {e^{7x}} \, dx \\v = e^7x/7$

Substitute the given values into the formula;

$\int\limits {xe^{7x}} \, dx = x(e^{7x}/7) + \int\limits ({e^{7x}/7}) \, dx\\\int\limits {xe^{7x}} \, dx = \frac{xe^{7x}}{7} + \frac{e^{7x}}{7*7} \\\int\limits {xe^{7x}} \, dx = \frac{xe^{7x}}{7} + \frac{e^{7x}}{49}$

3 0

3 years ago

Please Help me!!!

drek231 [11]

Step-by-step explanation:

The displacement of a particle d (in km) as a function of time t (in hours) is given by :

$d=2t^3+5t^2-3$

Displacement at t = 4 hours,

$d(4)=2(4)^3+5(4)^2-3=205\ km$

Velocity of particle is given by :

$v=\dfrac{dd}{dt}\\\\v=\dfrac{d(2t^3+5t^2-3)}{dt}\\\\v=6t^2+10t$

Velocity at t = 4 hours,

$v=6(4)^2+10(4)=136\ km/h$

Acceleration of the particle is given by :

$a=\dfrac{dv}{dt}\\\\a=\dfrac{d(6t^2+10t)}{dt}\\\\a=12t+10$

At t = 4 hours,

$a=12(4)+10=58\ km/h^2$

Therefore, the displacement, velocity and acceleration at t = 4 hours is 205 km, 136 km/h and 58 km/h² respectively.

7 0

3 years ago

7(3b-1)=2b-26 please help and give me step by step ☺️

Colt1911 [192]

Answer:

b = -1

Step-by-step explanation:

7(3b-1): 7 goes into the numbers by multiplying. This will give you 21b-7.

So now the equation should be like 21b-7=2b-26.

-7 and 2b swap places, making 21b-2b=7-26. It will give you 19b= -19.

Finally divide the two numbers (-19 / 19) and the solution will be b= -1.

If I didn't make a clear answer or a good explanation, please comment. I sometimes mess up my steps, and this is my first time using this.

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Answer:

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Write 763089 in words

Svet_ta [14]

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