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Rzqust [24]
3 years ago
13

The high temperatures in Montana are recorded for a week. High Temperatures Sunday 46°F Monday 52°F Tuesday 51°F Wednesday 54°F

Thursday 49°F Friday 51°F Saturday 61°F What is the mean, or average, high temperature for the week?
Mathematics
2 answers:
Elan Coil [88]3 years ago
5 0

Answer:


Step-by-step explanation:

to get the mean you need to add up all the numbers

46+52+51+54+49+51+61=364

then divide that sum by the amount of numbers you have

364 divided by 7=52

so the mean you have is 52 degrees

AnnyKZ [126]3 years ago
3 0
46+52+51+54+49+51+61=ans/7 which is 52°F
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A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the
Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1

Total outcomes:

12 peaches, from a set of 15. So

T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455

Probability:

p = \frac{D}{T} = \frac{1}{455} = 0.0021

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36

Total outcomes:

12 peaches, from a set of 15. So

T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455

Probability:

p = \frac{D}{T} = \frac{36}{455} = 0.0791

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

3 0
3 years ago
PLEASE ANSWER!!!!!!
Contact [7]

Answer:

The answer is D

Step-by-step explanation:

the first one is equal to the equation 4 < 3 because of absolute value, second 4 < 3, third 3 < -4, fourth -3 < 4

7 0
3 years ago
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The two slanted lines BC and AD are the same, then AD should be the same length, 27.
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4 years ago
I tried two ways to figure out 206-48 but both answers were different
konstantin123 [22]
158 is the answer to your question
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4 years ago
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What are the values of a and b?
Lady_Fox [76]

Answer:

a =17.08

b = 16.97

Step-by-step explanation:

What are the values of a and b?

Using pythagoras therem';

Hyp^2 = opp^2 + adj^2

Get the value of b;

18^2 = b^2 + 6^2

324 = b^2 + 36

b^2 = 324 - 36

b^2 = 288

b = √288

b = 16.97

Get the value of a;

b^2 + 2^2 = a^2

288 + 4 = a^2

292 = a^2

a^2  = 292

a = √292

a= 17.09

6 0
3 years ago
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