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Rzqust [24]
3 years ago
13

The high temperatures in Montana are recorded for a week. High Temperatures Sunday 46°F Monday 52°F Tuesday 51°F Wednesday 54°F

Thursday 49°F Friday 51°F Saturday 61°F What is the mean, or average, high temperature for the week?
Mathematics
2 answers:
Elan Coil [88]3 years ago
5 0

Answer:


Step-by-step explanation:

to get the mean you need to add up all the numbers

46+52+51+54+49+51+61=364

then divide that sum by the amount of numbers you have

364 divided by 7=52

so the mean you have is 52 degrees

AnnyKZ [126]3 years ago
3 0
46+52+51+54+49+51+61=ans/7 which is 52°F
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Step-by-step explanation:

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⇒ y = 2x + b ---- (1)

  • Step 2: The line passes through the point (4,2). So it will satisfy the equation. Find b by substituting x = 4 and y = 2.

⇒ 2 = 2 × 4 + b = 8 + b

⇒ b = -6

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Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl
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Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane n=(-2,-2,1), then r will have the next parametric equations:

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To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3

Substitute the value of \lambda in the parametric equations:

x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u

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The number of years it will take for 0.1% of potassium-40 to remain is obtained as follows:

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